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tatyana61 [14]
3 years ago
14

(x^3)^9 = A: x^12 B: x^27 C: x^3 D: x^6

Mathematics
1 answer:
Grace [21]3 years ago
3 0
(x^3)^9=x^{27}
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Evaluate the following expression (2.3)-3(1,1)
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Answer:

<em><u>2</u></em><em><u>.</u></em><em><u>3</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>3</u></em><em><u>,</u></em><em><u> </u></em><em><u>1</u></em><em><u>)</u></em><em><u> </u></em>

Step-by-step explanation:

1) Simplify  3 × (1, 1) 3 × (1, 1)  to  3× 1, 13 × 1,1.

<em>2</em><em>.</em><em>3</em><em> </em><em>-</em><em> </em><em>(</em><em> </em><em>3</em><em> </em><em>×</em><em> </em><em>1</em><em>,</em><em> </em><em>1</em><em> </em><em>)</em>

2) Simplify 3 × 1 to 3.

2.3 - ( 3, 1)

<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>2</u></em><em><u>.</u></em><em><u>3</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>3</u></em><em><u>,</u></em><em><u> </u></em><em><u>1</u></em><em><u>)</u></em><em><u>.</u></em>

3 0
3 years ago
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In a certain game, a player can solve easy or hard puzzles. A player earns 30 points for solving an easy puzzle and 60 points fo
Aleksandr-060686 [28]

Answer:  Second option.

Step-by-step explanation:

Let be "e" the number of easy puzzles Tina solved and "h"  the number of hard puzzles Tina solved.

Set up a system of equations:

\left \{ {{e+h=50} \atop {30e+60h=1,950 }} \right.

You can use the Eliminationn Method to solve this system of equations:

  • Multiply the first equation by -30.
  • Add the equations.
  • Solve for "h".

Therefore, through this proccedure, you get:

\left \{ {-30e-30h=-1,500} \atop {30e+60h=1,950 }} \right.\\.........................\\30h=450\\\\h=\frac{450}{30} \\\\h=15

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3 years ago
Which number has two lines of symmetry?
qaws [65]
I think the answer is d

4 0
2 years ago
What is 5 plus 2 1/4
svet-max [94.6K]

Answer:

7 1/4

Step-by-step explanation:

the 5 is not affecting the fraction so just add the whole numbers

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Using the exponential growth function for the U. S. population from 1970 through 2003:
jeka94

Answer:

Step-by-step explanation:

Using the exponential growth function for the U. S. population from 1970 through 2003:

A = 205.1e^0.011t

with the U.S. population being 205.1 million in 1970, when would the U. S. population reach 350 million?

A.

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B.

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C.

2018

D.

2038

We have the expression

A = 205.1e^0.011t

We are asked to find when would the U. S. population reach 350 million

A = 350

350 = 205.1e^0.011t

We divide both sides by 205.1

Divide both sides by 205.1

350/205.1 = 205.1e^0.011t/205.1

1.7064846416 = e^0.011t

We take the log of both sides

log 1.7064846416 = log e^0.011t

log 1.7064846416 = t log 0.011

t = log 1.7064846416/ log 0.011

t = 0.1185057826

7 0
3 years ago
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