Answer:
-1
Step-by-step explanation:
See the attachment for the polynomial long division. The constant in the quotient is -1.
_____
Here, there is a remainder of -x. If there were no remainder the constant in the quotient is the ratio of the constant in the dividend to the constant in the divisor: -2/2 = -1.
That could be a first guess in a "guess and check" solution approach.
<em>Guess</em>: first term of binomial quotient is (2x^3)/x^2 = 2x; last term of binomial quotient is -2/2 = -1. So, the quotient is guessed to be (2x -1).
<em>Check</em>: (2x -1)(x^2 -x +2) = 2x^3 -3x^2 +5x -2
Subtracting this from the actual dividend gives a remainder of -x. This has a lower degree than the divisor, so no further adjustment of the quotient is required.
Answer:
A
Step-by-step explanation:
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Answer:
4.3
Step-by-step explanation:
Apply trigonometric ratios to find the answer.
Firstly, we need to find the measure of angle theta. In order to do this, we will use triangle BAD.
From angle theta, the trigonometric ratio sine can be used:
sinθ = 
After we find the value, we take the inverse sine of it and the result is approximately 50.7 degrees.
Now, knowing that angles BAD and CAD are the same, we can solve for CD using trigonometric ratio sine.
sin50.7 = opposite/hypotenuse
sin50.7 = CD/5.5
sin50.7 * 5.5 = CD
4.3 ≈ CD
Answer:
On first visit, weight =550 g
Weight gained on second visit= 350 g
Weight gained on third visit= 300 g
Present weight=550+350+300= 1200
Weight gained=1200-550=650
Percentage of weight increased
-------->650/550 × 100 = 118.18\%
So the kitten gained 118% weigh
Step-by-step explanation:
Hello,
a(2)=-6
a(3)=-6*r
a(4)=-6*r²
a(5)=-6*r^3=162
a(5)/a(2)=r^3=162/(-6)=-27==>r=-3
a(1)=-6/(-3)=2
a(2)=2*(-3)
a(3)=2*(-3)²
a(4)=2*(-3)^3
a(5)=2*(-3)^4
a(n)=2*(-3)^(n-1)
Answer
