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Alex73 [517]
3 years ago
8

Can anyone help me please

Mathematics
1 answer:
natita [175]3 years ago
8 0

To find f^{-1} (x), you can switch the x and the y(which is f(x)).

So instead of f(x)=\frac{-7}{4x-5}, it will be:

x = \frac{-7}{4y-5}

Now you need to find "y".

You first multiply (4y - 5) on both sides

x(4y - 5) = -7

Next divide "x" on both sides

4y - 5 = \frac{-7}{x}

Add 5 on both sides

4y = \frac{-7}{x} +5

Divide 4 on both sides to get "y" by itself

y = \frac{7}{4x} +\frac{5}{4}


f^{-1} = \frac{7}{4x} +\frac{5 }{4}

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