Answer: There are approximately 853827 new cases in 6 years.
Step-by-step explanation:
Since we have given that
Initial population = 570000
Rate at which population decreases is given by
![\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D)
Now,
First year =570000
Second year is given by
![570000\times (\frac{1}{3})](https://tex.z-dn.net/?f=570000%5Ctimes%20%28%5Cfrac%7B1%7D%7B3%7D%29)
Third year is given by
![570000(\frac{1}{3})^2](https://tex.z-dn.net/?f=570000%28%5Cfrac%7B1%7D%7B3%7D%29%5E2)
so, there is common ratio ,
it becomes geometric progression, as there is exponential decline.
so,
![570000,570000\times \frac{1}{3},570000\times( \frac{1}{3})^2,......,570000\times (\frac{1}{3})^6](https://tex.z-dn.net/?f=570000%2C570000%5Ctimes%20%5Cfrac%7B1%7D%7B3%7D%2C570000%5Ctimes%28%20%5Cfrac%7B1%7D%7B3%7D%29%5E2%2C......%2C570000%5Ctimes%20%28%5Cfrac%7B1%7D%7B3%7D%29%5E6)
a=570000
common ratio is given by
![r=\frac{a_2}{a_1}=\frac{1}{3}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Ba_2%7D%7Ba_1%7D%3D%5Cfrac%7B1%7D%7B3%7D)
number of terms = 6
Sum of terms will be given by
![S_n=\frac{a(1-r^n)}{(1-r)}](https://tex.z-dn.net/?f=S_n%3D%5Cfrac%7Ba%281-r%5En%29%7D%7B%281-r%29%7D)
We'll put this value in this formula,
![S_6=\frac{570000(1-(\frac{1}{3})^6}{(1-\frac{1}{3})}\\\\=853827.16](https://tex.z-dn.net/?f=S_6%3D%5Cfrac%7B570000%281-%28%5Cfrac%7B1%7D%7B3%7D%29%5E6%7D%7B%281-%5Cfrac%7B1%7D%7B3%7D%29%7D%5C%5C%5C%5C%3D853827.16)
So, there are approximately 853827 new cases in 6 years.
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Answer:
A is 4
Step-by-step explanation:
A _ 8 _ _ _ _ _ _ _ _ 8 _ 6
A _ 8 _ _ _ _ _ _ _ _ 8 4 6
A _ 8 _ _ _ _ _ _ _ 6 8 4 6
A _ 8 _ _ _ _ _ _ 4 6 8 4 6
A _ 8 _ _ _ _ _ 8 4 6 8 4 6
A _ 8 _ _ _ _ 6 8 4 6 8 4 6
A _ 8 _ _ _ 4 6 8 4 6 8 4 6
A _ 8 _ _ 8 4 6 8 4 6 8 4 6
A _ 8 _ 6 8 4 6 8 4 6 8 4 6
A _ 8 4 6 8 4 6 8 4 6 8 4 6
A 6 8 4 6 8 4 6 8 4 6 8 4 6
4 6 8 4 6 8 4 6 8 4 6 8 4 6
A is 4
Hope this helps!
Answer:
substitute that value for x in the polynomial and see if it evaluates to zero
Step-by-step explanation:
A "zero" of a polynomial is a value of the polynomial's variable that make the expression become zero when it is evaluated. As an almost trivial example, consider the polynomial x-3. The value x = 3 is a zero because substituting that value for x makes the expression evaluate as zero.
3 -3 = 0
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Evaluating polynomials can be done different ways. Straight substitution for the variable is one way. Using synthetic division by x-a (where "a" is the value of interest) is another way. This latter method is completely equivalent to rewriting the polynomial to Horner form for evaluation.
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In the attachment, Horner Form is shown at the bottom.