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irina1246 [14]
4 years ago
5

How would I solve this equation for x? x/p + x/q = S

Mathematics
1 answer:
anzhelika [568]4 years ago
7 0
Your answer is: x=r/p+q

Here is what you do:

Factor x out of <span><span>px</span>+<span>qx</span></span><span><span>=x<span>(<span>p+q</span>)</span></span>=r</span>
Divide each term by <span>p+q </span>and simplify.<span>=x=<span>r/<span>p+q</span></span></span>
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Answer:

11.9

Step-by-step explanation:

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3 years ago
There are 10 sweets in a bag.
Valentin [98]

Answer:

See Explanation Below

Step-by-step explanation:

Given

Total Sweets = 10

Red = 4

Green = 2

Yellow = 3

Purple = 1

Required

a & b

The question is not properly presented; however the solution is as follows;

A.

Let P(Yellow) represent the probability of selecting a yellow sweet and n(Yellow) represent the number of Yellow sweets;

P(Yellow) = \frac{n(Yellow)}{Total}

P(Yellow) = \frac{4}{10}

P(Yellow) = 0.4

So, whichever letter that shows 0.4 or \frac{4}{10} is the probability of choosing a yellow sweet

B.

Let P(Orange) represent the probability of selecting an orange sweet and n(Orange) represent the number of orange sweets;

Since, there's no orange sweet in the bag;

n(Orange) = 0

P(Orange) = \frac{n(Orange)}{Total}

P(Orange) = \frac{0}{10}

P(Orange) = 0

In probability; opposite probabilities add up to 1;

Let P(Not\ Orange) represent the probability of choosing a sweet that is not orange

P(Not\ Orange)  + P(Orange) = 1

Substitute P(Orange) = 0

P(Not\ Orange)  + 0 = 1

P(Not\ Orange) = 1

So, whichever letter that shows 0 is the probability of choosing a sweet that is not orange

6 0
3 years ago
HELPP YALL! I WILL MARK BRAINIEST!! LOOK AT THE PICTURE!!
kow [346]

ok

then

sorry

really

sorry

:/

then im dum

just delete my answer

8 0
3 years ago
Read 2 more answers
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