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3 years ago

The graph of a polynomial is shown below. Between which two x-values does this polynomial have an extreme value?

Mathematics

1 answer:

stiv31 [10]3 years ago

7 0

Answer:

C.-3 to -2

Step-by-step explanation:

From the picture attached, it can be seen that an extreme value, that is, a maximum of the polynomial is found between x = -3 and x = -2. In this extreme point, the polynomial has an approximate value of 4.5

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what do you call the middle value in the set of the data or quantities a mean b. median c.mode d.range

MakcuM [25]

Answer:

median is the middle value

mean is the average

mode is the one that occurs most

range is the highest number - lowest number

6 0

3 years ago

ANSWER QUICKLY!Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2,

rosijanka [135]

Answer:

y=-2/3x+490

Step-by-step explanation:

When we look at this standard form equation, we can see that

2x+3y=1,470.

To convert this to slope-intercept form, we would simplify this equation to where y is on one side and everything else is on the other side.

2x+3y=1,470

-2x -2x

3y=-2x+1,470

÷3 ÷3

y=-2/3x+490

You would then graph that with -2/3 being your slope and (0,490) being your y-intercept.

Hope this helps!

7 0

4 years ago

Solve for c: −9c−12+3c=12

Doss [256]

Answer: c = -4

Step-by-step explanation: Isolate the variable by dividing each side by factors that don't contain the variable.

Hope this helps you out! ☺

7 0

3 years ago

Read 2 more answers

A sumo wrestling ring is circular and has a circumference of 4.6\pi \text{ meters}4.6π meters4, point, 6, pi, start text, space,

frez [133]

Answer:

The area of the sumo wrestling ring is $5.29 \pi$

Step-by-step explanation:

The circumference of the circular sumo wrestling ring is $4.6\pi$ , that means its radius $r$ is:

$2\pi r=4.6\pi$

$r=\frac{4.6}{2} =\boxed{2.3\:meters.}$

Now once we have the radius $r$ of the sumo wrestling ring we can find its area $A$ by the following formula:

$A=\pi r^2$

Putting in the value of $r=2.3\:meters$ we get:

$A=\pi (2.3m)^2=\boxed{5.29\pi\:\:m^2}$

Therefore the area of the sumo wrestling ring is ${5.29\pi\:\:m^2$

3 0

3 years ago

Read 2 more answers

Simplify without absolute value bars. <br><br>a. |w - 4| for w < 4<br><br>b. |w - 4| for w ≥ 4

FrozenT [24]

Answer:

See explanation

Step-by-step explanation:

Use definition of the absolute value of the number x:

$|x|=\left\{\begin{array}{l}x,\ x\ge 0\\-x,\ x$

1. When $w$ then $w-4$

so using the definition,

$|w-4|=-(w-4)=4-w$

2. When $w\ge 4,$ then $w-4\ge 0$

so using the definition,

$|w-4|=w-4$

3 0

3 years ago