Answer:
a. mg/c b. 4. It is the speed the object approaches as time goes on.
Step-by-step explanation:
a. Calculate lim v as t→[infinity]
Since v = mg/c(1 - e^ -ct/m)
mg/c(1 - e^(-c(∞)/m))
mg/c(1 - e^(-∞/m))
mg/c(1 - e^(-∞))
mg/c(1 - 0)
mg/c(1)
mg/c
b. What is the meaning of this limit?
4. It is the speed the object approaches as time goes on.
This is because, since t → ∞ implies a long time after t = 0, the limit of v as t → ∞ implies the speed of the object after a long time. So, the limit of v as t → ∞ is the speed the object approaches as time goes on.
-2x - 6 < 4
+ 6 + 6
--------------------
-2x < 10
------ -------
-2 -2
x < -5
If you were to graph the solution, the arrow would be going to the left. I know this because the the less than symbol in the answer is pointing to the left. It's kinda hard to tell, but that's the way I figure it out every time. Also, the circle you draw will not be shaded in because the symbol in the answer is greater than or equal to/less than or equal to.
Let me know if any of what I said doesn't make sense. I hope I could help!
Step-by-step explanation:
first you have to take all similar variable on the same side of the equation and the constants on the other side then solve the question .
example : -12x + 9 = -15x
-12x +15x = -9
3 x = -3
X = -3/3= -1
x = -1
like this you can solve all the other equation ..
<em>Hope </em><em>this </em><em>will </em><em>be</em><em> helpful</em><em> to</em><em> you</em><em> </em><em>.</em><em>.</em>
<em>plz </em><em>mark</em><em> my</em><em> answer</em><em> as</em><em> brainlist</em><em> </em><em>if </em><em>you</em><em> </em><em>find </em><em>it </em><em>useful</em><em>.</em><em>.</em>
Answer:
Step-by-step explanation:
Please refer to the image attached.
Here we have a circle with unit radius. At some angle Ф the radius = 1 , and it is the hypotenuse (shown by green line in the image attached) of the ΔPQR thus formed. As our angle Ф increases, the hypotenuse gets closer to the positive y axis and at 90°, it overlap the y axis. Hypotenuse (H) and Opposite site (O) becomes same and Adjacent (A) becomes 0.
As our angle move further and reaches 180, the Hypotenuse and adjacent becomes same and overlap negative x axis. As we move further at 270 i.e , the hypotenuse and opposite side overlap on y axis and Adjacent side become 0. However the opposite side becomes negative here .
Our sine ratio says
Hence we have our
Now
Adjacent as we discussed is 0 at