How many different pizzas can be ordered if the restaurant offers 15 different toppings and there is no limit to

2 answers:

7 0

The answer will be:

C(15,1) + C(15,2) + C(15,3) +...+ C(15,15)

The number will be huge. My current calculator cannot compute it

Reil [10]4 years ago

4 0

I am not extremely sure about this but I think the amount of different pizza that can be ordered is 15. Because, they offer exactly 15 different toppings. Right? No, probably wrong:(

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A rectangle. one side is 2x + 7 and the other is x+3

saveliy_v [14]

$\large{\green}\fcolorbox{purple}{pink}{\bf{\underline{\red{\color{red}Answer}}}}$

6x + 20

Step-by-step explanation:

To find :-

Perimeter of rectangle

Given :-

Length = 2x + 7

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Solution :-

We know that

$\mathfrak {perimeter \: of \: rectangle =2(length + breadth) }$

Now we will substitute the values of length and breadth

$\sf \longmapsto perimeter = 2 \{(2x + 7) + (x + 3) \} \\ \\ \\ \sf \longmapsto perimeter = 2 \{3x + 10 \} \\ \\ \\ \sf \longmapsto perimeter = 6x + 20$