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3 years ago

Someone help! you have 44 text messages in your inbox. How many messages can your cell phone hold? (and inbox is 88% full)

2 answers:

4 0

We can set up a proportion.

88% = 0.88

44/0.88 = x/1

Cross multiply:

0.88x = 44

Divide 0.88 to both sides:

x = 50

So your cell phone can hold 50 messages.

nadezda [96]3 years ago

4 0

Ratio and proportion 44/x=88/100 cross multiply x= 50 messages

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The mean of a set of eight numbers is 8 and the mean of a different set of twelve numbers is m. Given that the mean if the combi

Basile [38]

Mean=total/the number of values =>total=mean*the number of values
the total of the first set of 8 numbers is : total=8*8=64
the total of the second set of 12 numbers is: 12m
the total of the 20 numbers is: 64+12m
the mean of the 20 number is: (64+12m)/20=5
solve for m: 64+12m=100
12m=36
m=3

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3 years ago

A recipe for a large batch of brownies uses one kilogram of sugar. Another recipe uses 800 grams of flour. How much sugar is nee

Nady [450]

1,600 800+800=1,600 this is your answer

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3 years ago

Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ

Oksanka [162]

Standard form is ax+by=c

first we use
y-y1=m(x-x1)
a point is (x1,y1)
the slope is m

the slope between the points (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
given
(1,1) and (3,4)
slope=(4-1)/(3-1)=3/2

a oint is (1,1) and slope is 3/2
y-1=3/2(x-1)
y-1=3/2x-3/2
solve for ax+by=c form, a is normally positive and a and b and c are whole numbers
times 2 both sides
2y-2=3x-3
minus 2y
-2=3x-2y-3
add 3
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5 0

3 years ago

Two boats depart from a port located at (–8, 1) in a coordinate system measured in kilometers and travel in a positive x-directi

miss Akunina [59]

Answer:

$\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.$

Step-by-step explanation:

1st boat:

Parabola equation:

$y=ax^2 +bx+c$

The x-coordinate of the vertex:

$x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a$

Equation:

$y=ax^2 -2ax+c$

The y-coordinate of the vertex:

$y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10$

Parabola passes through the point (-8,1), so

$1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1$

Solve:

$c=10+a\\ \\80a+10+a=1\\ \\81a=-9\\ \\a=-\dfrac{1}{9}\\ \\b=-2a=\dfrac{2}{9}\\ \\c=10-\dfrac{1}{9}=\dfrac{89}{9}$

Parabola equation:

$y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}$

2nd boat:

Parabola equation:

$y=ax^2 +bx+c$

The x-coordinate of the vertex:

$x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0$

Equation:

$y=ax^2+c$

The y-coordinate of the vertex:

$y_v=a\cdot 0^2+c\Rightarrow c=-7$

Parabola passes through the point (-8,1), so

$1=a\cdot (-8)^2-7\\ \\64a-7=1$

Solve:

$a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7$

Parabola equation:

$y=\dfrac{1}{8}x^2 -7$

System of two equations:

$\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.$

7 0

3 years ago

Read 2 more answers

Calculate the length of a triangle if another length is 15 feet and the hypotenuse is 39 feet.

Y_Kistochka [10]

We have to use Pythagorean theorem that says :

$a^2+b^2=c^2\\\Rightarrow a^2+15^2=39^2\\a^2=39^2-15^2\\a=\sqrt{1296}\\a=36$

The missing length of the triangle is : 36 feet

3 0

3 years ago