Answer:
(1) Area of second triangle= 50 cm^2.
(2) Area of ΔABC=98 cm^2.
and Area of ΔDFG=175 cm^2.
Step-by-step explanation:
<em>" For two similar triangles the ratio of sides is equal to the ratio of square of their areas".</em>
i.e. if a,b are the corresponding sides of two similar triangles and let A and B denote the area of two triangles then we have the relation as:
(1)
for the first question:
we have a=2, b=5.
A=8 cm^2.
Hence,
B=50 cm^2.
Hence, the area of second triangle is 50 cm^2.
(2)
In second option we have:
a=6 and b=5.
A-B=77 cm^2.
A=77+B
Hence area of second triangle i.e. ΔDFG is 175 cm^2.
and area of first triangle i.e. ΔABC=175-77=98 cm^2.
To solve this, you just simply divide to get a decimal and then convert to a percentage.
2.5 divided by 9.2 is equal to approximately 0.2717.
You then multiply that by one hundred to get a percentage. So the final answer is approximately 27.17%.
Answer:
x=60,150,240,330
Step-by-step explanation:
Take the arc cot of both sides
Remember cotangent has a period of 180 degrees
where n is 0, 1,2,3,4,5.....
Isolate x.
where n is 0, 1,2,3,4,5,6.
Keep plugging in integers as long they are in the interval [0,360].
We get
60,150,240,330.
Since the exterior angle of a triangle is equal to the sum of the interior opposite angles, angle 5 = 90 + angle 1.
Given that angle 5 = 147, 147 = 90 + x.
x = 57 degrees.
So, angle 1 is 57 degrees.
