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mr Goodwill [35]
2 years ago
5

Can someone help me please

Mathematics
1 answer:
Ahat [919]2 years ago
5 0
This is a black screen!!!!
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The temperature dropped from 75° to 50°. what was the percent increase in the temperature?
Radda [10]

Answer:

33%

Step-by-step explanation:

25 / 75) x 100% = 33.33%

8 0
3 years ago
Find the derivative of <br><img src="https://tex.z-dn.net/?f=%20y%20%3D%20%5Csqrt%5B3%5D%7Bx%7D%20" id="TexFormula1" title=" y =
MAXImum [283]

Answer:

\displaystyle y'(27) = \frac{1}{27}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Exponential Rule [Root Rewrite]: \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}
  • Exponential Rule [Rewrite]: \displaystyle b^{-m} = \frac{1}{b^m}

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

<u>Step 1: Define</u>

y = ∛x

x = 27

<u>Step 2: Differentiate</u>

  1. [Function] Rewrite [Exponential Rule - Root Rewrite]:                               \displaystyle y = x^{\frac{1}{3}}
  2. Basic Power Rule:                                                                                         \displaystyle y' = \frac{1}{3}x^{\frac{1}{3} - 1}
  3. Simplify:                                                                                                         \displaystyle y' = \frac{1}{3}x^{-\frac{2}{3}}
  4. Rewrite [Exponential Rule - Rewrite]:                                                           \displaystyle y' = \frac{1}{3x^{\frac{2}{3}}}

<u>Step 3: Solve</u>

  1. Substitute<em> </em>in <em>x</em> [Derivative]:                                                                           \displaystyle y'(27) = \frac{1}{3(27)^{\frac{2}{3}}}
  2. Evaluate exponents:                                                                                     \displaystyle y'(27) = \frac{1}{3(9)}
  3. Multiply:                                                                                                         \displaystyle y'(27) = \frac{1}{27}

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

8 0
2 years ago
Read the ques
Dafna11 [192]

Answer:

0.25feet

Step-by-step explanation:

The equation is not well written. Let the equation of the height be modelled as;

h = -16d²+8d+4

The velocity of the ball is zero at its maximum height.

Velocity = change in displacement/time

v = dh/dd

Differentiate

v = -32d+8

Since dh/dd = v = 0

0 = -32d+8

Add 32d to both sides

0+32d = 8

32d = 8

Divide both sides by 32

32d/32 = 8/32

d = 1/4

d = 0.25feet

Hence the maximum height of the tennis ball is 0.25feet

Note that the modeled equation was assumed. You can apply the same calculation to any equation given

3 0
3 years ago
Find parametric equations through point P=(2,2,7) in the direction of the vector v = (44, 14, -20)?
ycow [4]

9514 1404 393

Answer:

  (x, y, z) = (2+44t, 2+14t, 7-20t)

Step-by-step explanation:

One way to write parametric equations for line L is ...

  L = P + t·<em>v</em>

where P is the given point and <em>v</em> is the given direction vector. Using that form, we have ...

  (x, y, z) = (2+44t, 2+14t, 7-20t)

__

If you like, you can remove a common factor of 2 from the coefficients of t.

  (x, y, z) = (2+22t, 2+7t, 7-10t)

5 0
2 years ago
M x+ B = y solve for B <br><br><br> A x+ B y = C solve for x <br><br><br> Bh/2 = A, solve for h
quester [9]

Step-by-step explanation:

Mx+B=y

B=y-Mx

Ax+By=C

Ax=C-By

Ax/A=C-By/A

x=C-By/A

Bh/2=A

2 x Bh/2=A x 2

Bh=2A

Bh/B=2A/B

h=2A/B

5 0
3 years ago
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