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dybincka [34]
3 years ago
12

A 9.00-cm-long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wi

re and rail is 0.320 Ω . Pulling the wire at a steady speed of 4.00 m/s causes 4.30 W of power to be dissipated in the circuit.
Physics
1 answer:
m_a_m_a [10]3 years ago
5 0

Answer:

<em>0.45 N</em>

Explanation:

<em>Let Recall that,</em>

<em> The power formula is:  </em>

<em>   P = E²/R  </em>

Let A = the magnetic field  

<em>Let L = length of wire  = 9.00cm = 0.09 m  </em>

let  R = resistance of wire  = 0.320 Ω

let v =  velocity of the wire = 4 m/s  

<em>Let E = across the wire voltage </em>

Let P = the power of the wire = 4.3 W  

To Solve  for E:  

<em>The formula of E = √PR  </em>

The Voltage from  a magnetic field is given as,

E = vAL  

We therefore Use E = E

√PR = vAL  

to solve  for A,

A= √PR/vL  

BA= √4.3(0.32)/(4)(.09)  -=0.173

A = 0.173 wA/m²

Let F  be  the pulling force  

Let I  be the current in the wire  

P = I²R  

<em>I = √P/R  </em>

F = IAL  

F = √P/RAL  

F = √4.3/.32(0.173)(.09)  

<em>F = 0.45N</em>

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