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Kryger [21]
3 years ago
13

Calculate the slope of the line that contains the points: (2,-3) and (6,-3)

Mathematics
1 answer:
pshichka [43]3 years ago
8 0

Answer:

Step-by-step explanation:

Slope (m) =

ΔY

ΔX

= 0

θ =

arctan( ΔY )

ΔX

= 0°

ΔX = 6 – 2 = 4

ΔY = -3 – -3 = 0

Distance (d) = √ΔX2 + ΔY2 = √16 = 4

Equation of the line:

y = 0x – 3

When x=0, y = -3

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Expanded FormExpanded form refers to a base and an exponent written as repeated multiplication. ExponentExponents are used to describe the number of times that a term is multiplied by itself. ExpressionAn expression is a mathematical phrase containing variables, operations and/or numbers.
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trapecia [35]

Answer:

∠ PQR = 70°

Step-by-step explanation:

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the area of a trapezoid is 780 cm squared. the shorter base is 48 cm and the height is 15 cm. Find the length of the other base
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3 years ago
Write an expression for the difference between 10 and x
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8 0
3 years ago
What is the equation in slope-intercept form of the line that passes through the points (0, −4) and (2, 0)?
Nastasia [14]

Answer:

y = 2x -4

Step-by-step explanation:

Slope intercept form is  y = mx + b where <em>m </em>is the slope and <em>b </em>is the y-intercept.

Slope is \frac{rise}{run} or \frac{y_2 - y_1}{x_2-x_1} in this case = \frac{0 - (-4)}{2 - 0} = \frac{4}{2} = 2

Substitute one of the coordinates for x and y. I am going to use (0, -4) so:

-4 = 2(0) + b\\-4 = 0 + b\\-4 = b

since m = 2 and b = -4, we can conclude that the equation would be

y = 2x -4

5 0
3 years ago
Read 2 more answers
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