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3 years ago

A rectangle has a width of x and a length that is 13 less than twice its width. Which rectangle shows the same relationship?

Mathematics

2 answers:

aleksandr82 [10.1K]3 years ago

8 0

The answer is the first one because
Twice it's width you don't know what the width is so
2x-13

Elena-2011 [213]3 years ago

5 0

The answer is the first one

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Using the Pythagorean Theorem, give an example of three sides of a right triangle

VikaD [51]

Answer:

Two legs and an hypotenuse

Step-by-step explanation:

Isn’t that what your looking for?

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3 years ago

1.<br> Use trigonometry to work out the value of x.<br> Not drawn accurately. <br> Help pls

tino4ka555 [31]

Answer:

20cos(39) or 15.543 (3 d.p.)

Step-by-step explanation:

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2 years ago

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xxMikexx [17]

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Step-by-step explanation:

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4 years ago

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7 + 54 / 3 (2) Solve the problem

vampirchik [111]

Answer:

Step-by-step explanation:

7 + 54/3*2

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4 years ago

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Suppose f (x) = x^2. Find the graph of f(x+2)

NISA [10]

$\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)={{ A}}({{ B}}x+{{ C}})+{{ D}}
\\\\
~~~~y={{ A}}({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)={{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\\\
f(x)={{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\\\
f(x)={{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\\\\
--------------------$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
~~~~~~\textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
~~~~~~if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
~~~~~~if\ {{ D}}\textit{ is negative, downwards}\\\\
~~~~~~if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind,

$\bf f(x)=x^2\qquad \quad f(x+2)=(x+2)^2\implies f(x+2)=\stackrel{A}{1}(\stackrel{B}{1}x\stackrel{C}{+2})^2\stackrel{D}{+0}$

C = 2 B = 1 C/B = 2/1 or +2, horizontal left shift of 2 units

f(x) shifted left by 2 units is f(x+2).

8 0

3 years ago