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arlik [135]
3 years ago
10

A rectangle has a width of x and a length that is 13 less than twice its width. Which rectangle shows the same relationship?

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
8 0
The answer is the first one because
Twice it's width you don't know what the width is so
2x-13
Elena-2011 [213]3 years ago
5 0
The answer is the first one
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Using the Pythagorean Theorem, give an example of three sides of a right triangle
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Two legs and an hypotenuse

Step-by-step explanation:

Isn’t that what your looking for?

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1.<br> Use trigonometry to work out the value of x.<br> Not drawn accurately. <br> Help pls
tino4ka555 [31]

Answer:

20cos(39) or  15.543 (3 d.p.)

Step-by-step explanation:

  • Use SOHCAHTOA
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At a New Car Dealership, a particular model comes in 3 different trim levels (CX, DX,
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B. 48

Step-by-step explanation:

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colors: 4

interior: 4

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4 years ago
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7 + 54 / 3 (2) Solve the problem
vampirchik [111]

Answer:

16

Step-by-step explanation:

7 + 54/3*2

simplify the fraction

=7 + 54/6

=7 + 9

= 16

7 0
4 years ago
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Suppose f (x) = x^2. Find the graph of f(x+2)
NISA [10]
\bf ~~~~~~~~~~~~\textit{function transformations}&#10;\\\\\\&#10;% templates&#10;f(x)={{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\\\&#10;~~~~y={{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\\\&#10;f(x)={{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\\\&#10;f(x)={{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\\\&#10;f(x)={{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\\\\&#10;--------------------

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\&#10;~~~~~~\textit{reflection over the x-axis}&#10;\\\\&#10;\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\&#10;~~~~~~\textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;~~~~~~if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;~~~~~~if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;~~~~~~if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind,

\bf f(x)=x^2\qquad \quad f(x+2)=(x+2)^2\implies f(x+2)=\stackrel{A}{1}(\stackrel{B}{1}x\stackrel{C}{+2})^2\stackrel{D}{+0}

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f(x) shifted left by 2 units is f(x+2).
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3 years ago
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