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Shalnov [3]
3 years ago
10

Which of the following equations will produce the graph shown?

Mathematics
1 answer:
Artemon [7]3 years ago
5 0
Try this option (it is not the only way):
the points (0;0) and (2;2) belong to the curve. Using the coordinates of these points it is possible to calculate the equation.
y= \frac{1}{2}x^2;
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(20 Points) <br><br><br> Perform the indicated operations.
JulijaS [17]

Answer:

5x-8/12y

Step-by-step explanation:

x+1

3y

+

x−2

4y

−(

x+3 /6y

=

30xy2−48y2

72y3

=

30x−48/72y

=

5x−8 /12y

7 0
3 years ago
If line ML is a midsegment of triangle IJK, find KJ
laila [671]
So what we're dealing with here is a similar triangle situation. Since ML is a midsegment, that means that IL and LJ are congruent. So, IL=LJ=13. This means that the whole side IJ is 26 (13+13=26). We also know that triangle IML and triangle IKJ are similar triangles, so their sides are proportional. This means that we can set up the ratio:
12/13 = x/26
and solve for x.
After multiplying 26 to both sides of the equation, we find that x=24, so KJ=24.
4 0
4 years ago
Read 2 more answers
All I need is the answer. Will be marked brainiest if it is absolutely correct.
NARA [144]
What’s the question?
6 0
3 years ago
(x - 5)2 = 25
Bezzdna [24]

<em>Here is your answer </em>

<em> x = 17.5</em>

<em>Make as brainliest plzz....</em>

<em>Hope this answer is helpful.</em>...

6 0
3 years ago
A rectangle is to be inscribed in an isosceles right triangle in such a way that one vertex of the rectangle is the intersection
svet-max [94.6K]

Answer:

x  =  2  cm

y  = 2  cm

A(max) =  4 cm²

Step-by-step explanation: See Annex

The right isosceles triangle has two 45° angles and the right angle.

tan 45°  =  1  =  x / 4 - y        or     x  =  4  -  y     y  =  4  -  x

A(r)  =  x* y

Area of the rectangle as a function of x

A(x)  =  x  *  (  4  -  x )       A(x)  =  4*x  -  x²

Tacking derivatives on both sides of the equation:

A´(x)  =  4 - 2*x             A´(x)  =  0            4   -  2*x  =  0

2*x  =  4

x  =  2  cm

And  y  =  4  - 2  =  2  cm

The rectangle of maximum area result to be a square of side 2 cm

A(max)  = 2*2  =  4 cm²

To find out if A(x) has a maximum in the point  x  =  2

We get the second derivative

A´´(x)  =  -2           A´´(x)  <  0   then A(x) has a maximum at  x = 2

5 0
2 years ago
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