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Rama09 [41]
3 years ago
9

Please Help its past due!

Mathematics
2 answers:
andreev551 [17]3 years ago
6 0
HEY THERE !!

YOUR ANSWER IS IN ATTACHMENT !!

See both attachments.

salantis [7]3 years ago
3 0

Draw or Cut two  similar squares with sides b+c units long.


Draw or cut four  pairs of similar right triangles with side lengths as indicated in the diagram.

Now arrange the similar triangles at the corners of the squares such that the sides b of one similar triangle plus the side c  of a second similar triangle coincides with the length of the square.


We do another arrangement of the similar triangles. This time arrange another 4 similar triangles in the opposite corners, such that each pair forms a square.

Now comparing the two different arrangements we got two different areas that are equal.

The area of the uncovered squares in the first arrangement is a^2

The area of the two uncovered squares in the second arrangement is b^2+c^2

Equating the two areas gives the Pythagoras Theorem

a^2=b^2+c^2

Note that  a is the hypotenuse, b and c are two shorter sides of the similar right triangles.




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Diano4ka-milaya [45]

Answer:

t_a = 7 s

t_w = 5 s

Step-by-step explanation:

Given:

- The average speed in air v_a = 16 m/s

- The average speed in water v_w = 3 m/s

- The total distance D = 127 m

- The total time T = 12 s

Find:

How long did the stone fall in air and how long did it fall in the water?

Solution:

- Lets time taken by stone to drop through air as t_a = t_a.

- The time taken in water would be t_w = (12 - t_a)

- The total distance covered can be calculated as:

                            D = v_a*t_a+ v_w*(12 - t_a)

                            127 = 16*t_a + 3*(12 - t_a)

Simplify and solve for t:

                            91 = 16*t_a - 3t_a

                            13*t_a = 91

                            t_a = 7 s

                            t_w = 5 s

                           

8 0
3 years ago
I rlly need help with this gr 11 math problem
prohojiy [21]

Answer:

a) \frac{d-5.50}{0.45}

b) The inverse function is a reflection of the original function across the line

y = x. For example, if the function f applied to an input x gives a result of y, then applying its inverse function g to y gives the result x. So you would use it to find the x-value at a y just like you use the original to find the y value at an x.

Step-by-step explanation:

To do an inverse of a function you first switch the independent variable (d) and the dependent variable (c).

d = 0.45c + 5.50

Then you solve for c

d - 5.50 = 0.45 c

c = (d-5.50)/0.45

8 0
3 years ago
Trapezoid ABCD is congruent to trapezoid . Which sequence of transformations could have been used to transform trapezoid ABCD to
dedylja [7]
The answer is D: Trapezoid ABCD was reflected across the y-axis and then rotated 90° counterclockwise around the origin
4 0
3 years ago
Please help meh on this for points and brainliest​
Oxana [17]

Answer:

13 is two and two thirds of four and seven eighths.

Step-by-step explanation:

To solve this, all you need to do is divide 13 by 2 and two thirds.  Let's do it:

13 \div 2\frac{2}{3}\\= 13 \div \frac{8}{3}\\= 13 \times \frac{3}{8}\\= \frac{13 \times 3}{8}\\= \frac{39}{8}\\= 4\frac{7}{8}

3 0
2 years ago
Read 2 more answers
Consider the following hypothesis test: H0: μ1 - μ2 = 0 Ha: μ1 - μ2 ≠ 0 There are two independent samples taken from the two pop
nlexa [21]

Answer:

The value of the test statistic is z = 1.78

Step-by-step explanation:

Before finding the test statistic, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Sample 1:

\mu_1 = 110, s_1 = \frac{7.2}{\sqrt{81}} = 0.8

Sample 2:

\mu_2 = 108, s_2 = \frac{6.3}{\sqrt{64}} = 0.7875

The test statistic is:

z = \frac{X - \mu}{s}

In which X is the sample mean, \mu is the value tested at the null hypothesis, and s is the standard error.

0 is tested at the null hypothesis:

This means that \mu = 0

Distribution of the difference:

X = \mu_1 - \mu_2 = 110 - 108 = 2

s = \sqrt{s_1^2+s_2^2} = \sqrt{0.8^2+0.7875^2} = 1.1226

What is the value of the test statistic?

z = \frac{X - \mu}{s}

z = \frac{2 - 0}{1.1226}

z = 1.78

The value of the test statistic is z = 1.78

5 0
3 years ago
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