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Alex_Xolod [135]
3 years ago
8

V-9/10v+6=11(hlp)this problem is confusing.

Mathematics
2 answers:
alexira [117]3 years ago
6 0
\frac{v-9}{10v} +6=11

Subtracting 6 on both sides, we get,

\frac{v-9}{10v} =11-6

\frac{v-9}{10v} =5

Multiplying by 10v on both sides , we get,

\frac{v-9}{10v}*10v =5 *10v

v-9=50v

-9 = 50v -v

-9=49v

\frac{-9}{49} =v

v=- \frac{9}{49}
Valentin [98]3 years ago
4 0
\frac{v-9}{10v+6}=11 \\\\ 11(10v+6)=v-9 \\\\ 110v+66=v-9 \\\\ 110v-v=-9-66 \\\\ 109v= -75 \\\\ \boxed{v=-\frac{75}{109}}
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Read 2 more answers
What radius of a circle is required to inscribe a regular hexagon with an area of 210.44 cm2 and an apothem of 7.794 cm
alekssr [168]
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[area of a regular hexagon]=6*[area of one <span>equilateral triangle]
</span>210.44=6*[area of one equilateral triangle]
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[area of one equilateral triangle]=b*h/2
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the length side of a regular hexagon is 9 cm
<span>applying the Pythagorean theorem
</span>r²=h²+(b/2)²------>r²=7.794²+(4.5)²------> r²=81--------> r=9 cm

<span>this last step was not necessary because the radius is equal to the hexagon side------> (remember the equilateral triangles)
</span>
the answer is
the radius is 9 cm
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