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andre [41]
4 years ago
6

Find Derivative (root3(6x^2))

Mathematics
2 answers:
mars1129 [50]4 years ago
7 0
This is the same as saying (6x^2)^3. We can take the derivative using the chain rule. With the chain rule, you multiply by the power, decrease the power by 1, and multiply by the derivative of the inside.

3(6x^2)^2*12x
or
36x*(6x^2)^2

Hope this helps<span />
trapecia [35]4 years ago
5 0
\bf \sqrt[3]{6x^2}\implies (6x^2)^{\frac{1}{3}}\implies 6^{\frac{1}{3}}x^{\frac{2}{3}}\\\\&#10;-----------------------------\\\\&#10;\cfrac{dy}{dx}=6^{\frac{1}{3}}\cdot \cfrac{2}{3}x^{\frac{2}{3}-1}\implies 6^{\frac{1}{3}}\cdot \cfrac{2}{3}x^{-\frac{1}{3}}\implies 6^{\frac{1}{3}}\cdot \cfrac{2}{3}\cdot \cfrac{1}{x^{\frac{1}{3}}}&#10;\\\\\\&#10;

\bf \cfrac{dy}{dx}=6^{\frac{1}{3}}\cdot \cfrac{2}{3x^{\frac{1}{3}}}\implies \cfrac{2\cdot 6^{\frac{1}{3}}}{3x^{\frac{1}{3}}}\implies \cfrac{2\sqrt[3]{6}}{3\sqrt[3]{x}}\implies \cfrac{2}{3}\sqrt[3]{\cfrac{6}{x}}
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PLEASEEE HURRY<br><br> Please please please
Andre45 [30]

Answer:

final answer is: ABC, A (-5,1), B (-4,6) and C (-1,4)

Step-by-step explanation:

Original: ABC, A (2,-1), B (1,4) and C (-2,2)

translate 3 units to the right and 2 units up: ABC, A (5,1), B (4,6) and C (1,4)

reflected over the x-axis: ABC, A (5,-1), B (4,-6) and C (1,-4)

rotated 180°: ABC, A (-5,1), B (-4,6) and C (-1,4)

7 0
3 years ago
Helpppppppppppppppppp
Anuta_ua [19.1K]

Option A:

\left(x^{4}\right)\left(3 x^{3}-2\right)\left(4 x^{2}+5 x\right)=12 x^{9} +15 x^{8} -  8 x^{6}-10 x^{5}

Solution:

Given expression \left(x^{4}\right)\left(3 x^{3}-2\right)\left(4 x^{2}+5 x\right).

To find the product of the above expression:

\left(x^{4}\right)\left(3 x^{3}-2\right)\left(4 x^{2}+5 x\right)

First multiply first two factors with each term.

           =(x^{4} \times 3 x^{3}- x^{4} \times 2 ) \left(4 x^{2}+5 x\right)

Using exponent rule: a^m \cdot a^n=a^{m+n}

            =(3 x^{7}- 2x^{4} ) \left(4 x^{2}+5 x\right)

Now multiply these two factors with each term.

            =3 x^{7} (4 x^{2}+5 x)- 2x^{4} \left(4 x^{2}+5 x\right)

            =(4 x^{2} \times 3 x^{7} +5 x \times 3 x^{7} )-  \left(4 x^{2} \times 2x^{4}+5 x \times 2x^{4}\right)

Using exponent rule: a^m \cdot a^n=a^{m+n}

            =(12 x^{9} +15 x^{8} )-  (8 x^{6}+10 x^{5})

           =12 x^{9} +15 x^{8} -  8 x^{6}-10 x^{5}

\left(x^{4}\right)\left(3 x^{3}-2\right)\left(4 x^{2}+5 x\right)=12 x^{9} +15 x^{8} -  8 x^{6}-10 x^{5}

Hence option A is the correct answer.

4 0
4 years ago
A store sells three different packs of the same yogurt. Which pack is the best buy? A) 8 containers for $4.04 B) 6 containers fo
Bas_tet [7]

Answer: C) 4 containers for $2.84

Step-by-step explanation:

8/4.04=1.98

6/3.46=1.73

4/2.84=1.41: best value

5 0
3 years ago
Read 2 more answers
I need help please can someone help
DENIUS [597]

Answer:

<h2>x = 8</h2>

Step-by-step explanation:

\sqrt{\dfrac{896z^{15}}{225z^6}}=\dfrac{xz^4}{15}\sqrt{14z}\\\\\sqrt{\dfrac{896z^{15}}{225z^6}}\qquad\text{use}\ \dfrac{a^m}{a^n}=a^{m-n}\\\\=\sqrt{\dfrac{(64)(14)z^{15-6}}{225}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b},\ \sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}\\\\=\dfrac{\sqrt{64}\cdot\sqrt{14}\cdot\sqrt{z^9}}{\sqrt{225}}=\dfrac{8\cdot\sqrt{14}\cdot\sqrt{z^{8+1}}}{15}\qquad\text{use}\ a^na^m=a^{n+m}\\\\=\dfrac{8\sqrt{14}\cdot\sqrt{z^8z}}{15}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}

=\dfrac{8\sqrt{14}\cdot\sqrt{z^8}\cdot\sqrt{z}}{15}=\dfrac{8\sqrt{14}\cdot\sqrt{z^{4\cdot2}}\cdot\sqrt{z}}{15}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\dfrac{8\sqrt{14}\cdot\sqrt{(z^4)^2}\cdot\sqrt{z}}{15}\qquad\text{use}\ (\sqrt{a})^2=a\\\\=\dfrac{8\sqrt{14}\cdot z^4\cdot\sqrt{z}}{15}=\dfrac{8z^4\sqrt{14}\cdot\sqrt{z}}{15}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\dfrac{8z^4\sqrt{14z}}{15}

\dfrac{8z^4\sqrt{14z}}{15}=\dfrac{xz^4\sqrt{14z}}{15}\iff x=8

5 0
3 years ago
A fifteen passenger van is rented for a family vacation. The van rental is $75.00 per day, plus a $160.00 insurance fee. How man
Amiraneli [1.4K]
760=75x+160
subtract 160
600=75x
divide 75 from 600
x=8 days
6 0
4 years ago
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