Let the boxes be Box 1, Box 2, Box 3.
consider the 3 white balls. They can be all of them in one box:
(3, 0, 0) (3 in Box 1, 0 in box 2 and 0 in box 0)
(0, 3, 0)
(0, 0, 3)
We can have 2 in one box, and 1 in one of the remaining boxes:
(2, 0, 1)
(2, 1, 0)
(0, 2, 1)
(1, 2, 0)
(0, 1, 2)
(1, 0, 2)
and there is only one way: (1, 1, 1) to place one white ball in each box
In total there are: 3+6+1=10 ways to place the white balls. Similarly there are 10 ways to place the black ones.
Since every placement of the white balls can be combined with any placement of the black balls, there are 10*10=100 ways to place the 3white balls and the 3 black bals in the boxes.
Answer: 100
Standard form;
(x - 2)² + (y - 6)² = 49
the center-radius form of the circle equation is in this format;
(x - h)² + (x - k)² = r²
so the center of the circle is; (2, 6)
so the radius of the circle is; 7
hope that helps, God bless!
Answer:
7
Step-by-step explanation:
the answer would be 7 because if there is 2 in per hour just go 2,4,6,8,10,12
and then count all the numbers i did and that will be your answer (7)
Answer:
same
Step-by-step explanation:
hope this helps
Number the tables as follows:
1 2
3 4
Eliminate 3 and 4 immediately, because for x = 2 the y values are wrong (3 and 1).
In tables 1 and 2, the input (1) produces the correct output (-1).
So we have to determine which table agrees 100% with the system of equations given.
Comparing tables 1 and 2, row by row, we see that their contents are the same EXCEPT for the first rows. So focus on determing which of those 2 rows displays values that satisfy both given equations.
First I looked at y=2x-5, and subst. -1 for x. I got -7, which is correct in table 1 but not in table 2 (where the value would be -13).
Thus, table 1 correct represents the solution of the system of equations.
