1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SashulF [63]
3 years ago
13

Astronomers measure large distances in light years. One light-year is the distance that light can travel in one year or approxim

ately 5,880,000,000,000 miles. Suppose a star is 14.4 light years from earth. In scientific notation, how many miles away is it?
A- 1.44x10 12 (12 is an exposed)
B- 5.88x10 12 miles away (12 is once again an exponent
C- 8.4672x10 13 13 is an exponet
D- 5.88 x 10 13 (13 is an exponet)
Mathematics
2 answers:
JulsSmile [24]3 years ago
6 0
14.4 * 5.88* 10^12
= 84.672 8 10^12
= 8.4672* 10^13   in scientific notation   

C is correct


Firlakuza [10]3 years ago
5 0

Answer:

Option C =8.4672\times10^{13}

Step-by-step explanation:

Given : Astronomers measure large distances in light years. One light-year is the distance that light can travel in one year or approximately 5,880,000,000,000 miles.

Suppose a star is 14.4 light years from earth.

To find : How many miles away a star is from earth?

Solution :

In 1 light-year the distance a light can travel is = 5,880,000,000,000 miles.

                                                                   or = 5.88\times 10^{12} miles

In 14.4 lights year the distance is  =14.4\times (5.88\times10^{12})

                                                        =84.672\times10^{12}

                                                    or =8.4672\times10^{13}

Therefore, Option C is correct - =8.4672\times10^{13}

You might be interested in
What is the value of x?<br><br><br><br> Enter your answer in the box.<br><br><br> _____ units
krek1111 [17]

Answer:

x=28

Step-by-step explanation:

We can use similar triangles and proportions to solve this problem.  Put the side of the small triangle over the same side of the larger triangle.

x               42

---------- = ----------

x+10           42+15

Simplify

x               42

---------- = ----------

x+10           57

Using cross products

57x = 42 (x+10)

Distribute

57x = 42x+420

Subtract 42x from each side

57x-42x = 42x-42x +420

15x = 420

Divide each side by 15

15x/15 = 420/15

x=28

6 0
3 years ago
Read 2 more answers
Need help for 16) and 19) Solve each equation and check. Show all work please
Paladinen [302]

Step-by-step explanation:

You said the other one would be the last haha just kidding I'm glad to help.

16. \frac{k}{2}=(-5)^2

First, get rid of that parenthesis.

\frac{k}{2}=25

Now multiply both sides by 2 so that you can isolate k

2(\frac{k}{2})=25*2

k=50

19. \frac{r}{3}=\frac{121}{11}

This is a pretty easy one. If you didn't know, 121/11 is actually 11 :)

\frac{r}{3}=11

Simply multiply by 3 to isolate r :)

3(\frac{r}{3})=11*3

r=33

4 0
3 years ago
Read 2 more answers
Urgent !!!!! triangle abc in the graph is a right triangle
cluponka [151]

Answer:

The third one

Step-by-step explanation:

If i'm wrong i'm srry

7 0
2 years ago
Read 2 more answers
Let $f(x) = x^2$ and $g(x) = \sqrt{x}$. Find the area bounded by $f(x)$ and $g(x).$
Anna [14]

Answer:

\large\boxed{1\dfrac{1}{3}\ u^2}

Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

Let's calculate the common points:

x^2=\sqrt{x}\qquad\text{square of both sides}\\\\(x^2)^2=\left(\sqrt{x}\right)^2\\\\x^4=x\qquad\text{subtract}\ x\ \text{from both sides}\\\\x^4-x=0\qquad\text{distribute}\\\\x(x^3-1)=0\iff x=0\ \vee\ x^3-1=0\\\\x^3-1=0\qquad\text{add 1 to both sides}\\\\x^3=1\to x=\sqrt[3]1\to x=1

The area to be calculated is the area in the interval [0, 1] bounded by the graph g(x) and the axis x minus the area bounded by the graph f(x) and the axis x.

We have integrals:

\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}

6 0
3 years ago
F(x)=2x(x+1) write in general form
arsen [322]
The general form of a quadratic expression is as follows
f(x) = a {x}^{2} + bx + c

Therefore, the given formula in general form would be:
f(x) = 2x(x + 1)
f(x) = 2x \times x + 2x \times 1
f(x) = 2 {x}^{2} + 2x
3 0
3 years ago
Other questions:
  • What is the midpoint of a line segment with the endpoints (-4,-3) and (7,-5)
    7·1 answer
  • What is the square root of 25
    9·2 answers
  • Can someone please help me with this!! I will award brainliest and 15 points for best answer!!
    13·1 answer
  • how do the graphs of f(x) = sin x and g(x) = sin2x+3 compare. Must make two selections of the following that apply.
    13·2 answers
  • Solve 2(3x+3)=2(4x) and 2(7x-2)=2x+4
    11·2 answers
  • Help, please I can't answer it
    14·1 answer
  • Please solve with proper explanation please <br>​
    12·1 answer
  • HELP PLS I'LL MARK YOU BRAINLIST
    15·1 answer
  • If m&gt; 17 which is a possible value for m help me
    11·1 answer
  • Find the equation of the line.<br> Use exact numbers.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!