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sertanlavr [38]
4 years ago
13

An athletics coach states that the distribution of player run times (in seconds) for a 100-meter dash is normally distributed wi

th a mean equal to 13.00 and a standard deviation equal to 0.2 seconds. What percentage of players on the team run the 100-meter dash in 13.30 seconds or faster? (Round your answer to two decimal places.)
Mathematics
1 answer:
Fofino [41]4 years ago
3 0

Answer:

6.68%

Step-by-step explanation:

First find the z-score:

z = (x − μ) / σ

z = (13.30 − 13.00) / 0.2

z = 1.50

Look the value up in a z-score table, or use a calculator.

P(z>1.50) = 1 − 0.9332

P(z>1.50) = 0.0668

6.68% of players on the team run the 100 meter dash in 13.30 seconds or faster.

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Answer:

The sample mean is \bar{x}=1.24 and the sample median is 0.56

Step-by-step explanation:

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\bar{x}=\frac{\sum x_i}{n}

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The sample median is obtained by first ordering the <em>n</em> observations from smallest to largest (with any repeated values included so that every sample observation appears in the ordered list). Then,

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8 0
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