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kiruha [24]
3 years ago
5

What is 21/99 in a decimal form

Mathematics
1 answer:
Norma-Jean [14]3 years ago
7 0

Answer:

0.2121~

Step-by-step explanation:

It's a repeating number. 0.0212121212

You might be interested in
Solve the equation, and check the solutions √(x+9)/4=3.
nadya68 [22]

Answer:

Solution: x = 135

Step-by-step explanation:

Hi there!

First, let´s write the equation:

√(x + 9) /4 = 3

Multiply by 4 both sides of the equation

√(x + 9) = 12

square both sides of the equation

x + 9 = 144

subtract 9 to both sides of the equation

x = 135  

Let´s check the solution:

√(x + 9) /4 = 3

x = 135

√(135 + 9) /4 = 3

√(144) /4 = 3

12/4 = 3

3 = 3

Then, x = 135 is the solution to the equation.

Have a nice day!

8 0
3 years ago
A school administrator is interested in estimating the proportion of students in the district who participate in community servi
jarptica [38.1K]

Answer: option 1

Step-by-step explanation: By constructing a 99% confidence interval for population proportion, it implies that the principal is 99% sure that the confidence interval will contain the population proportion.

When we construct confidence interval, we do so to show that the population parameter that we are looking for is present in the interval at a specified confidence level.

4 0
3 years ago
The larger of two number is 15 more than three times the smaller number if the sum of the two numbers is 63 find The numbers
Aleks [24]

The two numbers are <u>12 and 51.</u>

<h3>EXPLANATION</h3>

To solve this, I did 63-15, to get 48.

I then divided this by 4, to get the first number, which is <u>12.</u>

To find the second answer, I multiplied 12 by 3, which is 36, and then added the 15 back on, to get <u>51.</u>

<u>51 + 12 = </u><em><u>63</u></em>

3 0
3 years ago
Yara is opening a new bank account today.
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Getting 10% a month is the best option if she put $500 in.  That would be $50 the first month. $55 the second month etc. -- which would be more than the $500 in answer 1.

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3 years ago
Translate this word phrase into an equation:
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