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saul85 [17]
3 years ago
9

A(t)=934(1/2)t/30 for 20 years and 100 years

Mathematics
1 answer:
vichka [17]3 years ago
3 0
\bf A(t)=934\left( \frac{1}{2} \right)^{\frac{t}{30}}\qquad \qquad \stackrel{t=20}{A(t)=934\left( \frac{1}{2} \right)^{\frac{20}{30}}\implies A(t)=934\left( \frac{1}{2} \right)^{\frac{2}{3}}}
\\\\\\
\stackrel{t=100}{A(t)=934\left( \frac{1}{2} \right)^{\frac{100}{30}}\implies A(t)=934\left( \frac{1}{2} \right)^{\frac{10}{3}}}

nothing to it, t = year, and  you can just plug that in your calculator.
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Answer:

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Step-by-step explanation:

Now, we know that angles 1 and 2 are congruent, because they have the same angle measures. Now, looking at their positions, we can see that they are alternate exterior angles.

By the converse of the Alternate Exterior Angle, (I do not remember exactly how the theorem went) if two lines are cut by a transversal and have congruent alternate exterior angles, then the lines are parallel. Using this theorem, we can find that lines s and t are parallel, because they are cut by a transversal and their alternate exterior angles are congruent.

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