Answer:
(0,4) vertex and (1,3) another pt
Step-by-step explanation:
The parabola has been shifted up 4 units from parent function (there is also a reflection)...but we only really care about the shift 4 units up from (0,0) for our vertex... Our vertex is (0,4)
Now just plug in another number to find another point...let's do x=1
Plug in you get -1^2+4=-1+4=3 so another point is (1,3)
Answer:
Is the second expression written correctly? It reduces to y>-2, since no x is in the equation.
Step-by-step explanation:
We can graph the two equations. See attached image. If y>2 is the correct expression, all points to the right.
If the equation was meant to read y=-3x+1, then graph the revised expression.
The function f(x) = 6^(x)-2 has an x-intercept at approximately <span>(0.39, 0)
f(x) = 0 = 6^(x) - 2
2 = 6^(x)
log(2)/log(6)= x
x = 0.3868 = 0.39</span>
The answer to this question is A) (0.39, 0).
Answer:
Step-by-step explanation:
