Beth is planning a playground and has decided to place the swings in such a way that they are the same distance from the jungle
gym and the monkey bars. If Beth places the swings at point D, how could she prove that point D is equidistant from the jungle gym and monkey bars? If bisects , then point D is equidistant from points A and B because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects. If bisects , then point D is equidistant from points A and B because congruent parts of congruent triangles are congruent. If bisects , then point D is equidistant from points A and B because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects. If bisects , then point D is equidistant from points A and B because congruent parts of congruent triangles are congruent.
2 answers:
This question requires a diagram to show the position of point D. I found an attachment with the same question which I attached it along with this answer.
Answer:
If AC = BC, then point D is equidistant from points A and B because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects
Step-by-step explanation:
A line CD is a perpendicular line to line ACB intersecting point C. To understand it easier, if ACB is a horizontal lines, D is a point directly on top of C.
Any point directly on C which perpendicular to line ACB will always the same to the endpoint of the segments.
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