Answer:
35x16=560
Step-by-step explanation:
The area of the given trapezoid will be the sum of the areas of the triangular part and the rectangular part.
Now, the area of the rectangle,
is:
squared yards
Likewise, the area,
of the triangle will be:

Thus, the area of the trapezoid=
Thus the first option is the correct option.
The standard deviation of the set is 5.2
To find standard deviation, we take the square root of the variance.
Answer:
<h3>The event

denotes the complement of event A.</h3><h3>The value of

is 0.001</h3>
Step-by-step explanation:
Given that A denotes some event .
And also given that P(A)=0.999
<h3>To find the value of

:</h3>
Here the event
denotes the complement of event A Therefore
contains all the events that does not occur in A.
We know that the total probability is 1
So we have that




Hence the complement of event A is 
<h3>Therefore the value is

</h3>
All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

Multiply both sides by <em>r</em> :

Subtract the latter sum from the first, which eliminates all but the first and last terms:

Solve for
:

Then as gets arbitrarily large, the term
will converge to 0, leaving us with

So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18