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3 years ago

Answer to this please ?

Mathematics

1 answer:

stepan [7]3 years ago

8 0

Answer:

(-a,b)

Step-by-step explanation:

You use midpoint formula which is (x1+x2/2),(y1+y2/2)

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Answer please brainliested

lorasvet [3.4K]

Answer:

y=-x

Step-by-step explanation:

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2 years ago

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WILL GIVE BRAINLIEST ANSWER

solniwko [45]

Answer:

its C I think

Step-by-step explanation:

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3 years ago

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I need the answer to this fast Please

jeyben [28]

The initial function is slope

=> slope = 7-1/6-0 = 6/6 = 1

Hope this helps you :)

5 0

1 year ago

A percent is a rate in which the first term is compared to ______

PIT_PIT [208]

Answer:

From what we know about percentages and unit rates, the correct options are:

1) 100

2) 1

What is a percent?

Suppose we have an amount A, this would be the 100%.

If we want to know how much a quantity B represents, compared to A, we have:

A = 100%

B = x

where x is a percentage, to find the value of x we compute:

x = (B/A)*100%

While there is a dependence on A, we actually are comparing the term with 100 (because A represents a 100%), so the correct option is A: 100

PLS MARK ME AS THE BRAINLIST!!!

6 0

1 year ago

HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270

BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

$\large \boxed{sin \theta = tan \theta cos \theta} \\ \large \boxed{tan^{2} \theta + 1 = {sec}^{2} \theta}$

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

$\large{ {4}^{2} + 1 = {sec}^{2} \theta } \\ \large{16 + 1 = {sec}^{2} \theta } \\ \large{ {sec}^{2} \theta = 17}$

As we know, sec²θ = 1/cos²θ.

$\large \boxed{sec \theta = \frac{1}{cos \theta} } \\ \large \boxed{ {sec}^{2} \theta = \frac{1}{ {cos}^{2} \theta} }$

And thus,

$\large{ {cos}^{2} \theta = \frac{1}{17}} \\ \large{cos \theta = \frac{ \sqrt{1} }{ \sqrt{17} } } \\ \large{cos \theta = \frac{1}{ \sqrt{17} } \longrightarrow \frac{ \sqrt{17} }{17} }$

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

$\large{cos \theta = \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta = - \frac{ \sqrt{17} }{17}}$

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

$\large{sin \theta = 4 \times ( - \frac{ \sqrt{17} }{17}) } \\ \large{sin \theta = - \frac{4 \sqrt{17} }{17} }$

Answer

sinθ = -4sqrt(17)/17 or A choice.

4 0

3 years ago