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Ratling [72]
3 years ago
8

Solve the system using elimination: -5x + 3y = 2 for x -5x - 5y = -30 for y

Mathematics
1 answer:
LiRa [457]3 years ago
3 0

Hey there! :)

Equation 1 : -5x + 3y = 2

Equation 2 : -5x - 5y = -30

Because both equations contain a like term (which in this case is 5x), we can easily subtract these equations from one another.

Subtract equation 1 from equation 2 :

-5x - (-5x) = 0

3y - (-5y) = 3y + 5y --> 8y

2 - (-30) = 2 + 30 --> 32

This leaves us with 8y = 32. Simplify this to get y by dividing both sides by 8.

8y ÷ 8 = 32 ÷ 8

Simplify.

y = 4

Now, plug in 4 for y in our first equation.

-5x + 3(4) = 2

Simplify.

-5x + 12 = 2

Subtract 12 from both sides.

-5x = 2 - 12

Simplify.

-5x = -10

Divide both sides by -5.

-5x ÷ -5 = -10 ÷ -5

Simplify.

x = 2

Therefore, our answer is :

(2, 4) where x = 2, y = 4

~Hope I helped!~

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Which equation represents an exponential function that passes through the point (2, 80)?
Lena [83]

The function f(x) = 5(x)⁴, and f(x) = 5(4)ˣ represents the function that passes through the point (2, 80) option second and fourth are correct.

<h3>What is an exponential function?</h3>

It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent \rm y = a^x

where a is a constant and a>1

We have; an exponential function that passes through the point (2, 80).

f(x) = 4(x)⁵

Plug (2, 80) in the abovew function:

f(2) = 4(2)⁵ = 128 (false)

f(x) = 5(x)⁴

Plug (2, 80) in the abovew function:

f(2) = 5(2)⁴ = 80 (true)

f(x) = 4(5)ˣ

f(2) = 4(5)² = 100 (false)

f(x) = 5(4)ˣ

f(2) = 5(4)² = 80 (true)

Thus, the function f(x) = 5(x)⁴, and f(x) = 5(4)ˣ represents the function that passes through the point (2, 80) option second and fourth are correct.

Learn more about the exponential function here:

brainly.com/question/11487261

#SPJ1

4 0
2 years ago
How many one-fifths pieces of pizza are in 5 pizzas
SSSSS [86.1K]
10 1/5 times 5/1 add the zero
5 0
3 years ago
Read 2 more answers
Mr. Green is still repairing that old, rundown house he recently purchased. He finally fixed that leaky faucet in the kitchen, b
Murrr4er [49]

Answer:

960 ounces in 1 day

(Sorry for a late response, I just logged on)

Step-by-step explanation:

Most of that information is negligable (not important) besides 8 ounces in 12 minutes.

so an hour is 60 minutes, if we multiply both parts of the problem by 5 we get

40 ounces in 1 hour

a day is 24 hours, so if we multiply both sides by 24 well get our answer

960 ounces a day

-- Gage Millar, Algebra 1/2 tutor

8 0
3 years ago
Read 2 more answers
Please help.
Luba_88 [7]

Answer:

6.5%

Step-by-step explanation:

The original price of the ticket was 100% of the price of the ticket.

The 15% coupe reduced the price to 85% of the price of the ticket.

The 10% fee on the discounted price adds 10% of 85% to 85%, so it adds 8.5% to 85%. By adding the fee he is at 93.5% of the original price.

100% - 93.5% = 6.5%

The overall percent off compared to the original price was 6.5%.

Answer: 6.5%

4 0
3 years ago
Water is leaking out of a large barrel at a rate proportional to the square rooot of the depth of the water at that time. If the
sdas [7]

Answer:

It will take about 35.49 hours for the water to leak out of the barrel.

Step-by-step explanation:

Let y(t) be the depth of water in the barrel at time t,  where y is measured in inches and t in hours.

We know that water is leaking out of a large barrel at a rate proportional to the square root of the depth of the water at that time. We then have that

                                                 \frac{dy}{dt}=-k\sqrt{y}

where k is a constant of proportionality.

Separation of variables is a common method for solving differential equations. To solve the above differential equation you must:

Multiply by \frac{1}{\sqrt{y}}

\frac{1}{\sqrt{y}}\frac{dy}{dt}=-k

Multiply by dt

\frac{1}{\sqrt{y}}\cdot dy=-k\cdot dt

Take integral

\int \frac{1}{\sqrt{y}}\cdot dy=\int-k\cdot dt

Integrate

2\sqrt{y}=-kt+C

Isolate y

y(t)=(\frac{C}{2} -\frac{k}{2}t)^2

We know that the water level starts at 36, this means y(0)=36. We use this information to find the value of C.

36=(\frac{C}{2} -\frac{k}{2}(0))^2\\C=12

y(t)=(\frac{12}{2} -\frac{k}{2}t)^2\\\\y(t)=(6 -\frac{k}{2}t)^2

At t = 1, y = 34

34=(6 -\frac{k}{2}(1))^2\\k=12-2\sqrt{34}

So our formula for the depth of water in the barrel is

y(t)=(6 -\frac{12-2\sqrt{34}}{2}t)^2\\\\y(t)=\left(6-\left(6-\sqrt{34}\right)t\right)^2\\

To find the time, t, at which all the water leaks out of the barrel, we solve the equation

\left(6-\left(6-\sqrt{34}\right)t\right)^2=0\\\\t=3\left(6+\sqrt{34}\right)\approx 35.49

Thus, it will take about 35.49 hours for the water to leak out of the barrel.

5 0
4 years ago
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