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Vinil7 [7]
2 years ago
7

A cabinet is 1.5 meters tall. If 1 meter is approximately 1.09 yards, how tall is the cabinet, in yards?

Mathematics
1 answer:
Firlakuza [10]2 years ago
3 0

Answer:

1.64041995 yards

Step-by-step explanation:

If one meter is 1.09 yards, just add half that amount.

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X^3-3x^2-22x+24
the first option is the answer

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A factory machine produces kilograms of chocolate every minutes. At what rate does the machine produce chocolate?
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The question says kilograms every minutes, so it's C or D. The answers on A and B same
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the perimeter of a triangle is 59 in. The longest side is 11in. longer than the medium side, and the medium side is 3in longer t
Nataly_w [17]
Let the length of shortest side be - x
length of medium side - x +3
length of longest side - x +3 + 11
so , according to question
=> x + x +3 + x +3 + 11 = 59
=> x + x +x + 3 + 3 + 11 = 59
=> 3x = 59 - 17
=> 3 x = 42
=> x = 42/3
=> x = 14
Shortest side = x = 14
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4 0
3 years ago
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. y = 8 sin(x
V125BC [204]

Answer with explanation:

The equation of two curves are

y=8 sin x

y=8 cos x

The point of intersection of two curves are

→8 sin x=8 cos x

sinx = cos x

x=\frac{\pi}{4}\\\\y=8\sin\frac{\pi}{4}\\\\y=4\sqrt{2}

When you will look between points , 0 and x=\frac{\pi}{4}\\\\y=8\sin\frac{\pi}{4}\\\\y=4\sqrt{2},the curve obtained is right angled triangle.

Now, rotate the curve that is right angled triangle along the line , y= -1, to obtain a shape similar or resembling with Right triangular prism.

Draw a circular disc in the right triangular prism , having radius =x,and small part on the triangle having length dx.dx varies from 0 to \frac{\pi}{4}.

Required volume of solid obtained

    =\int\limits^{\frac{\pi}{4}}_0 {8 \sin x} \, dx \\\\=|-8\cos x|\left \{ {{x=\frac{\pi}{4}}} \atop {x=0}} \right.\\\\=8-4\sqrt{2}

    =8-4√2 cubic units    

5 0
3 years ago
Please help. 10 points. Please do not guess. Guesses will be reported.
Alex73 [517]

The inscribed angle theorem says that

m\angle CAB=\dfrac12m\angle COB

Triangle AOC is isosceles because both AO and CO are radii of the circle and have the same length. This means angles CAO and ACO have the same measure and are congruent.

Angles ACO and COD are congruent because they form an alternating interior pair between the parallel lines AC and OD.

Taking all these facts together, we have

m\angle COB=2m\angle COD

and since angle COB is made up of angles COD and DOB, these angles must be congruent, and so the arcs they subtend (CD and DB, respectively) must also congruent.

3 0
3 years ago
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