Answer:
foot
Step-by-step explanation:
Answer:
See Below
Step-by-step explanation:
We are given 3 equations.
3x + 8
5x - 20
and
5x + 4y
First lets solve for x using the first two
3x + 8 = 5x -20
Move the variables to one side
3x + 8 = 5x -20
-3x -3x
8 = 2x -20
+20 +20
28 =2x
28/2 =2x /2
14 = x
Now we have x = 14
Lets plug this into the second equation to solve for the angle
3(14) + 8
42 + 8 = 50
5(14) - 20
70 - 20 =50
Now, lets plug the x and the angle into the third equation to find y
5 (14) +4y = 50
70 + 4y = 50
-70 -70
4y = -20
4y/4 = -20/4
y = -5
So now we have:
x = 14
y = -5
and the angle = 50
Hope this helps!
Your answer should be 486 inches, you do 9x9 to find the area of one of the faces, and because there is 6 faces, you multiply that answer (81) to get 486
Answer: The hook would be 2.2 inches (approximately) above the top of the frame
Step-by-step explanation: Please refer to the picture attached for further details.
The top of the picture frame has been given as 9 inches and a 10 inch ribbon has been attached in order to hang it on a wall. The ribbon at the point of being hung up would be divided into 5 inches on either side (as shown in the picture). The line from the tip/hook down to the frame would divide the length of the frame into two equal lengths, that is 4.5 inches on either side of the hook. This would effectively give us two similar right angled triangles with sides 5 inches, 4.5 inches and a third side yet unknown. That third side is the distance from the hook to the top of the frame. The distance is calculated by using the Pythagoras theorem which states as follows;
AC^2 = AB^2 + BC^2
Where AC is the hypotenuse (longest side) and AB and BC are the other two sides
5^2 = 4.5^2 + BC^2
25 = 20.25 + BC^2
Subtract 20.25 from both sides of the equation
4.75 = BC^2
Add the square root sign to both sides of the equation
2.1794 = BC
Rounded up to the nearest tenth, the distance from the hook to the top of the frame will be 2.2 inches
- 2x - 11 = - 25 :) hope this is ok