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anygoal [31]
3 years ago
13

A batch of cookies requires 1 1/2 cups of sugar. How many batches can Tu make with 7 1/2 cups of sugar?

Mathematics
1 answer:
Korvikt [17]3 years ago
7 0
You would subtract 1 1/2 from 7 1/2 so the answer would be 6 hope I helped
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The sum of 14 and a number is equal to 17
Andrews [41]

Answer:

<h2>n + 14 = 17</h2><h2>n = 3</h2>

Step-by-step explanation:

Sum of 14 and number means "n + 14" and equals 17 means "= 17."

Now that we have an equation, we can solve.

<h3>Step 1: Subtract 14</h3>

n = 3

<h3>Step 2: Check</h3>

3 + 14 = 17

17 = 17 ✔

I'm always happy to help :)

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3 years ago
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The answer is “housing expenses”
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ASAP!!! Please answer the FIRST TWO and LAST TWO, ignore the answer asking for a graph.
ch4aika [34]

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Step-by-step explanation:

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3 years ago
7x+(-7)=9x-7 what is the answer?
erastova [34]

Answer:

x=0

Step-by-step explanation:

7x+(-7)=9x-7

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7x+(-7)7=9x-7+7

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Subtract 7x from each side

7x-7x = 9x-7x

0 = 2x

Divide by 2

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5 0
3 years ago
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On average 20% of the gadgets produced by a factory are mildly defective. I buy a box of 100 gadgets. Assume this is a random sa
Softa [21]

Answer:

a) P(A)=P(x

b) P(A)\approx 0.085

Step-by-step explanation:

The proportion of defective gadgets for this factory is p=0.2.

If a sample of n=100 gadgets is taken from the production, we can model the amount of defectives gadgets in this sample as a binomial random variable.

The probability of having k defectives in the sample can be written as:

P(x=k)=\binom{100}{k}p^k(1-p)^{100-k}

Then, we can write the expression to calculate the probabilities of A: "less than 15 gadgets are mildly defective":

P(A)=P(x

If we approximate this binomial distribtution to a normal distribution, we can calculate the new parameters as:

\mu=np=100*0.2=20\\\\\sigma=\sqrt{np(1-p)}=\sqrt{100*0.2*0.8}=\sqrt{16}=4

The continuity factor is applied for the change from a discrete distribution (binomial) to a continous distribution (normal). Then we have:

P(A)=P(X

Now, we can calculate the probability P(A):

z=(X-\mu)/\sigma=(14.5-20)/4=-5.5/4=-1.375\\\\P(A)=P(X

5 0
4 years ago
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