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2 years ago

Find the period of the function

Mathematics

1 answer:

Ostrovityanka [42]2 years ago

4 0

Answer:

6π

Step-by-step explanation:

The period indicates after which time the sine wave repeats.

You divide 2π by the factor in front of your function variable. This is 1/3 for your function.

So 2π/(1/3) = 6π

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What is the solution of the equation? w - 2 = -3

Viktor [21]

I think the answer would be c

6 0

2 years ago

The product of a number and 7, decreased by the number is equal to 42. Find the number.

evablogger [386]

$7$
this is the answer, its pretty simple. I'm not sure the mathematical procedures but if you plug in 7 you get 49. Then all you got to do is subtract by 7, because the question states the number is the same. So basically,
$7(7) - 7 = 42$

8 0

2 years ago

Which of the following inequalities is correct?

almond37 [142]

Answer:

Step-by-step explanation:

because there variables represent 1 so 1 cant be bigger than one and the other two have real equations

6 0

2 years ago

What two numbers multiply to 54 and add up to 7

k0ka [10]

Xy = 54
x + y = 7

$xy = 54$
$\frac{xy}{x} = \frac{54}{x}$
$y = \frac{54}{x}$

$x + y = 7$
$x + \frac{54}{x} = 7$
$\frac{x^{2}}{x} + \frac{54}{x} = 7$
$\frac{x^{2} + 54}{x} = 7$
$x^{2} + 54 = 7x$
$x^{2} - 7x + 54 = 0$
$x = \frac{-(-7) \± \sqrt{(-7)^{2} - 4(1)(54)}}{2(1)}$
$x = \frac{7 \± \sqrt{49 - 216}}{2}$
$x = \frac{7 \± \sqrt{-167}}{2}$
$x = \frac{7 \± i\sqrt{167}}{2}$
$x = \frac{7 \± 12.9i}{2}$
$x = 3.5 \± 6.45i$
$x = 3.5 + 6.45i$ $or$ $3.5 - 6.45i$

x + y = 7
3.5 + 6.45i + y = 7
- (3.5 + 6.45i) - (3.5 + 6.45i)
y = 3.5 - 6.45i
  (x, y) = (3.5 + 6.45i, (3.5 - 6.45i)

  or

  x + y = 7
3.5 - 6.45i + y = 7
- (3.5 - 6.45i)   - (3.5 - 6.45i)
y = 3.5 + 6.45i
(x, y) = (3.5 - 6.45i, 3.5 + 6.45i)

The two numbers that add up to 7 and can multiply to 54 is 3.5 ± 6.45i.

5 0

3 years ago

Cual es la sustitución de x/2+3=7

Maslowich

Answer:

conio

Step-by-step explanation:

5 0

2 years ago