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jenyasd209 [6]
3 years ago
5

Find the period of the function

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
4 0

Answer:

6π

Step-by-step explanation:

The period indicates after which time the sine wave repeats.

You divide 2π by the factor in front of your function variable. This is 1/3 for your function.

So 2π/(1/3) = 6π

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What is the inverse of the function f(x) = x +3?
OLga [1]

Answer:

h(x) = x - 3

Step-by-step explanation:

To find the inverse of a function, you can switch the x and y variables.

In f(x) = x + 3, the y variables is "f(x)".

y = x + 3

Now switch the x and y.

x = y + 3

Isolate for y and replace with h(x).

x - 3 = y

y = x - 3

h(x) = x - 3

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3 years ago
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I WILL GIVE CROWN PLS HELP NEED RIGHT ANSWER
FromTheMoon [43]

Answer:

Step-by-step explanation:

Surely you can figure out how many stairs she has to climb. She has to go down 4, back up to 0, and then up another 4, then back to 0

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3 years ago
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I know you want to answer this question.
Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

\frac{1}{2} ^{x-4} - 3 = 4^{x-3} - 2

First, convert 4^{x-3} to base 2:

4^{x-3} = (2^{2})^{x-3}

\frac{1}{2} ^{x-4} - 3 = (2^{2})^{x-3} - 2

Next, convert \frac{1}{2} ^{x-4} to base 2:

\frac{1}{2} ^{x-4} = (2^{-1})^{x-4}

(2^{-1})^{x-4} - 3 =  (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{-1})^{x-4} = 2^{-1*(x-4)}

2^{-1*(x-4)} - 3 = (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{2})^{x-3} = 2^{2(x-3)}

2^{-1*(x-4)} - 3 = 2^{2(x-3)} - 2

Apply exponent rule: a^{b+c} = a^{b}a^{c}:

2^{-1(x-4)} = 2^{-1x} * 2^{4}, 2^{2(x-3)} = 2^{2x} * 2^{-6}

2^{-1 * x} * 2^{4} - 3 = 2^{2x} * 2^{-6} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

2^{-1x} = (2^{x})^{-1}, 2^{2x} = (2^{x})^{2}

(2^{x})^{-1} * 2^{4} - 3 = (2^{x})^{2} * 2^{-6} - 2

Rewrite the equation with 2^{x} = u:

(u)^{-1} * 2^{4} - 3 = (u)^{2} * 2^{-6} - 2

Solve u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2:

u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2

Refine:

\frac{16}{u} - 3 = \frac{1}{64}u^{2} - 2

Add 3 to both sides:

\frac{16}{u} - 3 + 3 = \frac{1}{64}u^{2} - 2 + 3

Simplify:

\frac{16}{u} = \frac{1}{64}u^{2} + 1

Multiply by the Least Common Multiplier (64u):

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify:

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify \frac{16}{u} * 64u:

1024

Simplify \frac{1}{64}u^{2} * 64u:

u^{3}

Substitute:

1024 = u^{3} + 64u

Solve for u:

u = 8

Substitute back u = 2^{x}:

8 = 2^{x}

Solve for x:

x = 3

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3 years ago
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Answer:

40

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3 years ago
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tino4ka555 [31]

Answer:

D.   (27x^6y^9) / x^9.

Step-by-step explanation:

(3x^2y^3 / z^3 )^3

=  3^3 x^(2*3)y(3*3) / z^(3^3)

= 27 x^6y^9 / x^9.

4 0
4 years ago
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