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Setler79 [48]
3 years ago
7

Find the average value have of the function h on the given interval. h(u) = (15 − 10u)−1, [−1, 1]

Mathematics
1 answer:
Phantasy [73]3 years ago
3 0
-20 is the correct answer
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Stop wasting them

Step-by-step explanation:

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What is two hundred sixty-five thousandths in standard form?
Debora [2.8K]

Answer:

10^-1*2.65

Step-by-step explanation:

two hundred sixty-five thousandths= 0.265

We need a number between 1 and 10, to do the multiplication in standard form, so 0.265 turns into 2.65.

Because 2.65 becomes, smaller we use a negative power. We only move the decimal place once to the left, so we would multiply 2.65 by 10^1.

10^-1*2.65=0.265

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If g(x)= 2x^4+3x^3-x^2, find g(-1)
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4 years ago
Find the missing coefficient.<br><br> -<br> y2 − [-5y − y(-7y − 9)] − [-y (15y + 4)] = 0
maria [59]
There is only one solution in the given equation -y2 − [-5y − y(-7y − 9)] − [-y (15y + 4)] = 0. In solving this problem, apply first PEMDAS (parenthesis, exponents,multiplication, division, addition, subtraction). Then equation will transform into -y2+5y-7y2-9y+15y2+4y=0. Combine terms with same power and achieve 7y2=0. Divide both sides with 7 and perform square root of zero. Since the root is zero, we have one solution of the given equation which is y=0.
5 0
3 years ago
Read 2 more answers
What are the coordinates of the x-intercepts of the parabola y = x² - 8x + 15?
tamaranim1 [39]

Answer:

(3, 0) and (5, 0)

Step-by-step explanation:

we have

y=x^{2}-8x+15

we know that

The x-intercepts are the values of x when the value of y is equal to zero

so

For y=0

x^{2}-8x+15=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2}-8x+15=0  

so

a=1\\b=-8\\c=15

substitute in the formula

x=\frac{-(-8)\pm\sqrt{-8^{2}-4(1)(15)}} {2(1)}

x=\frac{8\pm\sqrt{4}} {2}

x=\frac{8\pm2} {2}

x=\frac{8+2} {2}=5

x=\frac{8-2} {2}=3

so

x=3, x=5

therefore

The x-intercepts are (3,0) and (5,0)

4 0
3 years ago
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