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3 years ago

Find the measure of angle x in the figure below:

Mathematics

1 answer:

Sav [38]3 years ago

6 0

Answer:

70 degrees

Step-by-step explanation:

The angle opposite x and x itself are vertical angles, meaning that they have the same angle measure. Since the sum of the interior angles of a triangle is 180 degrees:

x+55+55=180

x+110=180

x=180-110=70

Hope this helps!

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On the weekend, Jane bikes to her

Katen [24]

Answer:

4 x 40 = 160, 160 x11= 1760+2= 1762

Step-by-step explanation:

3 0

3 years ago

9 less than the product of 37 and x

zepelin [54]

Alrighty, so, 9 less hints to subtract. The product of 37 and x means that you're multiplying 37 and x. Therefore, I believe the answer that you're looking for is 37x-9.

Hope this helps! (:

8 0

3 years ago

Need help with school

denpristay [2]

Answer: 139°

Reasoning:

Angle 3 and 5 are congruent, so you can put their expressions equal to each other and solve.

14x-1=9x+14

To isolate the x to one side, subtract the 9x from the 14x.

5x-1=14

Now to get the constants on one side, add the 1 to the 14.

5x=15

Now divide both sides by 5 to isolate the x.

5x/5=15/5

x=3

Now that we know that, we can figure out angle 3.

9(3)+14

27+14= 41

Angle 3 = 41°

Now that we know what angle 3 is, we can subtract it from 180° to figure out angle 8 since angle 3 and 8 are supplemtary angles, aka linear pairs.

180°- 41°= 139°

<h3>Double checking your answer:</h3>

41°+139°=180°

3 0

3 years ago

Find the constant of proportionality k. Then write an equation for the relationship between x and y

ExtremeBDS [4]

Question:

Find the constant of proportionality k. Then write an equation for the relationship between x and y

$\begin{array}{ccccc}x & {2} & {4} & {6} & {8} \ \\ y & {10} & {20} & {30} & {40} \ \ \end{array}$

Answer:

(a) $k = 5$

(b) $y = 5x$

Step-by-step explanation:

Given

$\begin{array}{ccccc}x & {2} & {4} & {6} & {8} \ \\ y & {10} & {20} & {30} & {40} \ \ \end{array}$

Solving (a): The constant of proportionality:

Pick any two corresponding x and y values

$(x_1,y_1) = (2,10)$

$(x_2,y_2) = (6,30)$

The constant of proportionality k is:

$k = \frac{y_2 - y_1}{x_2 - x_1}$

$k = \frac{30-10}{6-2}$

$k = \frac{20}{4}$

$k = 5$

Solving (b): The equation

In (a), we have:

$(x_1,y_1) = (2,10)$

k can also be expressed as:

$k = \frac{y- y_1}{x- x_1}$

Substitute values for x1, y1 and k

$5 = \frac{y- 10}{x- 2}$

Cross multiply:

$y - 10 = 5(x - 2)$

Open bracket

$y - 10 = 5x - 10$

Add 10 to both sides

$y - 10 +10= 5x - 10+10$

$y = 5x$

6 0

3 years ago

Help me on this question! Jake can carry 6 1/4 pounds of wood in from the barn.His father can carry 1 5/7 times as much as jake.

ioda

$\text{ Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }$

Solution:

From given question,

Number of pounds Jake carry = $6\frac{1}{4} \text{ pounds }$

Number of pounds his father carry is $1\frac{5}{7}$ times as much as jake

To find: Number of pounds Jake father can carry

Convert the mixed fractions to improper fractions

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

$\rightarrow 6\frac{1}{4} = \frac{4 \times 6+1}{4} = \frac{25}{4}\\\\\rightarrow 1\frac{5}{7} = \frac{7 \times 1+5}{7} = \frac{12}{7}$

Then according to question,

$\text{Pounds father carry } = \frac{12}{7} \text{ times the pounds jake carry }\\\\\text{Pounds father carry } = \frac{12}{7} \times \frac{25}{4}\\\\\text{Pounds father carry } = \frac{75}{7}\\\\\text{In terms of mixed fractions, }\\\\\text{Pounds father carry } = \frac{75}{7} = 10\frac{5}{7}$

$\text{ Thus, Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }$

3 0

3 years ago