Answer:
(1.2)
(2.1)
What is the slope of the line passing through -4,6 and 3,-8
2 answers:
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Answer:
Step-by-step explanation:
<u><em>The correct question is</em></u>
what is the equation for a line passing through (-2,3) and perpendicular to y= -1/2<em>x</em>+1 ?
Remember
If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes are equal to -1)
The slope of the given line is m=-1/2
so
the opposite reciprocal is m=2
<em>Find the equation of the line in point slope form</em>
we have
substitute
<em>Convert to slope intercept form</em>
isolate the variable y
Answer:
f(x) > 0 over the interval
Step-by-step explanation:
If f(x) is a continuous function, and that all the critical points of behavior change are described by the given information, then we can say that the function crossed the x axis to reach a minimum value of -12 at the point x=-2.5, then as x increases it ascends to a maximum value of -3 for x = 0 (which is also its y-axis crossing) and therefore probably a local maximum.
Then the function was above the x axis (larger than zero) from , until it crossed the x axis (becoming then negative) at the point x = -4. So the function was positive (larger than zero) in such interval.
There is no such type of unique assertion regarding the positive or negative value of the function when one extends the interval from to -3, since between the values -4 and -3 the function adopts negative values.