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Arturiano [62]
3 years ago
15

consider the polynomial 6x^4+24x^3-72x^2. what is the greatest common factor of the terms of the polynomial

Mathematics
1 answer:
mash [69]3 years ago
7 0

First, look at the coefficients, 6, 24, -72. 6 is a factor of 6, 24, and -72. Since one of the coefficients is in fact 6, then 6 is the GCF of the coefficinets.

Now look at the variables. You have x^4, x^3, and x^2. Remember what the exponents mean. They mean a multiplication of several factors of x.

x^4, x^3, x^2 mean xxxx, xxx, xx

xxxx, xxx, xx have 2 factors of x in common, so the greatest common factor of the variables is xx which is the same as x^2.

When you put together the common factor of the coefficients and the common factor of the variable parts, you get GCF = 6x^2.

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Sav [38]

Answer with explanation:

We have to prove that, For any integer m, 2 m×(3 m + 2) is divisible by 4.

We will prove this result with the help of Mathematical Induction.

⇒For Positive Integers

For, m=1

L HS=2×1×(3×1+2)

      =2×(5)

       =10

It is not divisible by 4.

⇒For Negative Integers

For, m= -1

L HS=2×(-1)×[3×(-1)+2]

      =-2×(-3+2)

       = (-2)× (-1)

       =2

It is not divisible by 4.

False Statement.

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3 years ago
Find the x value for point C such that AC and BC form a 2:3 ratio.
Veronika [31]
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4 years ago
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If ƒ(x) = 2x² + 3, then which of the following represent ƒ(x + 1)?
Oliga [24]
This is a bit harder. I suggest getting the Domain and Range for the function of x.
If any of these answers have, an infinite domain and (3, infinite) range. That will be your answer.

Your answer is B.

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3 0
3 years ago
What is the domain and range of the graph shown?​
marissa [1.9K]

Answer:

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[0, infinity)

7 0
3 years ago
Solve for x in the given interval.<br><br> sec x= -2√3/3, for π/2 ≤x≤π
drek231 [11]

Answer:

b. x=\frac{5\pi}{6}

Step-by-step explanation:

The given function is

\sec x=-\frac{2\sqrt{3} }{3},\:\:for\:\:\frac{\pi}{2}\le x \le \pi

Recall that the reciprocal of the cosine ratio is the secant ratio.

This implies that;

\frac{1}{\cos x}=-\frac{2\sqrt{3} }{3}

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\Rightarrow \cos x=-\frac{\sqrt{3}}{2}

We take the inverse cosine of both sides to obtain;

x=\cos^{-1}(-\frac{\sqrt{3}}{2})

x=\frac{5\pi}{6}

4 0
4 years ago
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