Algebra Calculator
I will solve your equations by substitution.<span><span><span>12y</span>=4</span>;<span><span>x−<span>5y</span></span>=18</span></span>
Step: Solve<span><span> 12y</span>=4</span>for y:<span><span><span>12y/</span>12</span>=<span>4/12</span></span>(Divide both sides by 12)<span>y=<span>13</span></span>Step: Substitute <span>1/3 </span>for y in<span><span><span> x−<span>5y</span></span>=18</span>:</span><span><span>
</span></span><span><span>x−<span>5y</span></span>=18</span><span><span>
</span></span><span><span>x−<span>5<span>(<span>1/3</span>)</span></span></span>=18</span><span><span>
</span></span><span><span>x+<span><span>−5/</span>3</span></span>=18</span>(Simplify both sides of the equation)<span><span><span>
</span></span></span><span><span><span>x+<span><span>−5</span>/3</span></span>+<span>5/3</span></span>=<span>18+<span>5/3</span></span></span>(Add 5/3 to both sides)<span>
</span><span>x=<span>59/3</span></span>
Answer:<span><span>x=<span><span><span>59/3</span> and </span>y</span></span>=<span>1/<span>3</span></span></span>
Answer:
£1638.40
Step-by-step explanation:
Step one:
Given data
A car costs £5000 when new
Each year the value decreases by 20%.
Step two:
let us compute the worth in the next 5 years
year 1
worth= 5000- 0.2*5000
worth= 5000-1000
worth= £4000
year 2
worth= 4000- 0.2*4000
worth= 4000-800
worth= £3200
year 3
worth= 3200- 0.2*3200
worth= 3200-640
worth= £2560
year 4
worth= 2560- 0.2*2560
worth= 2560-512
worth= £2048
year 5
worth= 2048- 0.2*2048
worth= 2048-409.6
worth= £1638.40
The person is wrong because after 5 years the car is worth £1638.40
1 KG = .001 metric tons. Move the decimal point over three to make it 48.567 metric tons.
Answer:
1.23 meters
Step-by-step explanation: