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Alecsey [184]
3 years ago
15

How to do this? (#21 and #23)

Mathematics
2 answers:
ziro4ka [17]3 years ago
6 0

Answer:

21. g(x) = f(x-1); 23. g(x) = -ƒ(x)  

Step-by-step explanation:

21. ƒ(x) = log₃x

The graph is shifted one unit to the right.

One unit must have been subtracted from x.

g(x) = -f(x-1) = log₃(x-1)

Figure 1 shows ƒ(x) (blue) and g(x) (green) shifted one unit to the right,

23. f(x) = \log_{\frac{1 }{ 2}}x

The graph is inverted.

ƒ(x) must have been multiplied by -1.

g(x) = -ƒ(x)

g(x) = -\log_{\frac{1 }{ 2}}x

Figure 2 shows ƒ(x) (purple) and g(x) = -ƒ(x) (black).

Readme [11.4K]3 years ago
4 0

Answer:

\large\boxed{21.\ g(x)=f(x-2)+1\to g(x)=\log_3(x-2)+1}\\\\\boxed{22.\ g(x)=f(x)-4\to g(x)=3^x-4}\\\\\boxed{23.\ g(x)=-f(x)\to g(x)=-\log_{\frac{1}{2}}x}

Step-by-step explanation:

f(x) + n - shift the grapf n units up

f(x) - n - shift the grapf n units down

f(x + n) - shift the grapf n units to the left

f(x - n) - shift the grapf n units to the right

-f(x) - reflection about the x-axis

f(-x) - reflection about the y-axis

============================================

Look at the picture.

21.\\f(x)=\log_3x\\\\g(x)=\log_3(x-2)+1

move the graph 2 units to the right and 1 unit up

22.\\f(x)=3^x\\\\g(x)=3^x-4

move the graph 4 units down

23.\\f(x)=\log_{\frac{1}{2}}x\\\\g(x)=-\log_{\frac{1}{2}}x

reflection the graph about the X axis.

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measure a and measure b are vertical angles with measure a = x and measure b = 4x - 30. what is measure a?
Zolol [24]

Answer:

∠a = 10°

Step-by-step explanation:

The measure of ∠a = x

The measure of ∠b = 4x-30

It is also mentioned that the measure a and measure b are vertical angles. We need to find the value of a.

For vertically opposite angles,

∠a = ∠b

x = 4x-30

or

4x-30=x

Taking like terms together,

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3x = 30

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So, the meausre of ∠a is equal to 10°.

3 0
3 years ago
Simplify completely 8x^3 ÷ 6x^2 - 4x / -2x
artcher [175]

Answer:

Simplified form is -(\frac{8x^{3}}{3x-2}).

Step-by-step explanation:

The given expression is 8x^{3}\div \frac{6x^{2}-4x}{-2x}

We can rewrite the given expression as = 8x^{3}\times (-\frac{2x}{{6x^{2}-4x}})

Further simplification of the expression gives =\frac{-16x^{4}}{6x^{2}-4x}

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So the simplified of the given expression is =[tex]-(\frac{8x^{3}}{3x-2})

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t=tickets

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How many triangles does it make
GuDViN [60]
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