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sineoko [7]
3 years ago
5

Let f(x)=−12(x+2)2+5 . What is the average rate of change for the quadratic function from x=−3 to x = 1?

Mathematics
1 answer:
aev [14]3 years ago
5 0

Answer:

Average rate of change = -6

Step-by-step explanation:

The average rate of change over the interval (a,b) is given by;

[ f(b) - f(a)] / (b-a)........................where interval is (a,b)

(a,b) interval =(-3,1)

Where;

f(x)= -12 (x+2)² +5

f(a)=f(-3)=-12(-3+2)^2+5\\f(a)=f(-3)=-12(-1)^2+5\\f(a)=f(-3)=-12(1)+5\\=-12+5=-7\\\\\\f(b)=f(1)=-12(1+2)+5\\f(b)=f(1)=-12(3)+5\\=-36+5=-31\\\\f(b)-f(a)=-31--7=-24\\\\b-a=1--3=4\\\\f(b)-f(a)/b-a=\frac{-24}{4} =-6

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(6 - 1) + (3m)i = -12 + 27i
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Answer:

We want to solve the equation:

(6 - 1) + (3m)i = -12 + 27i

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first, we can rewrite this as:

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3*m*i = -12 - 5 + 27*i

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And we can write m as:

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3*(a + b*i)*i = -17 + 27*i

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