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Strike441 [17]
3 years ago
9

What is are/the zeroes of this function? Show work .

Mathematics
1 answer:
Nikolay [14]3 years ago
3 0
g(x) =  \dfrac{3x^2 + 5x + 2}{x^2+ 4x + 3}

g(x) = \dfrac{ (3x + 2)(x + 1)}{  (x + 3)(x + 1)}


g(x) = \dfrac{3x + 2}{x + 3}

when g(x) = 0,

\dfrac{3x + 2}{x + 3} = 0

3x + 2 = 0

3x = -2

x =  -\dfrac{3}{2}


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