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enot [183]
3 years ago
6

Question 1 (10 points)

Mathematics
1 answer:
Len [333]3 years ago
8 0

Answer:

C. Tan 40 = 60/x

Step-by-step explanation:

Reference angle = 40°

Opposite side to reference angle = 60

Adjacent side = x

Apply trigonometric function TOA,

Tan 40 = Opp/Adj

Tan 40 = 60/x

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Calculate the length of the unknown side of this right angled triangle
Murrr4er [49]

Answer:

≈ 12.05

Step-by-step explanation:

Pythagora

x = √(9² + 8²)

= √(81 + 64)

= √145

≈ 12.05

3 0
3 years ago
Will give Brainlyest. ASAP
crimeas [40]

Answer:

The correct answer is B. 36.87

Step-by-step explanation:

7 0
3 years ago
The reciprocal of a fraction less than 1 is always a fraction greater than 1.why is this?
Rama09 [41]
First of all, you know that a fraction is smaller than 1 if the top number is smaller than the bottom. It works both ways, meaning that if the top number is larger than the bottom number, the fraction is greater than 1.

So, for example, a fraction less than 1 can be expressed as
(x-1)/x
because the top number is smaller than the bottom number.

The reciprocal can be found by flipping the top and the bottom, so the reciprocal is
x/(x-1)

x is always greater than x-1, so in the reciprocal, the top number will be larger than the bottom number. That means it will always be greater than 1.

Hope this helps!
(Sorry if this is confusing)
4 0
3 years ago
2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de
Marianna [84]

Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

               M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let (x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

⇒ d=\sqrt{(2-5)^2+(4-3)^2}

⇒d=\sqrt{9+1}

⇒d=\sqrt{10}   ....(1)

Now, we find the length of M'K'

let (x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)

d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}

⇒ d^{'}=\sqrt{(-2+5)^2+(3-4)^2}

⇒d^{'}=\sqrt{9+1}

⇒d^{'}=\sqrt{10} .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct


3 0
4 years ago
Read 2 more answers
C С 154 -Y Х 2 3 5 w 4 6 7 Z D​
Sergio [31]

Answer:

m<1 = 26°

m<2 = 154°

m<3 = 26°

m<4 = 26°

m<5 = 154°

m<6 = 154°

m<7 = 26°

Step-by-step explanation:

What is required was not stated, however, let's find the value of every angle labelled in this diagram.

✔️m<1 = 180° - 154° (linear pair theorem)

m<1 = 26°

✔️m<2 = 154° (vertical angles theorem)

m<2 = 154°

✔️m<3 = m<1 (vertical angles theorem)

m<3 = 26° (substitution)

✔️m<4 = m<3 (alternate interior angles theorem)

m<4 = 26° (substitution)

✔️m<5 = m<2 (alternate interior angles theorem)

m<5 = 154° (substitution)

✔️m<6 = m<5 (vertical angles theorem)

m<6 = 154° (substitution)

✔️m<7 = m<4 (vertical angles theorem)

m<7 = 26° (substitution)

5 0
3 years ago
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