Answer: We can find out the missing statement with help of below explanation.
Step-by-step explanation:
We have a rectangle ABCD with diagonals AC and BD ( shown in given figure.)
We have to prove: Diagonals AC and BD bisect each other.
In triangles, AED and BEC.
( By alternative angle theorem)
( Because ABCD is a rectangle)
( By alternative angle theorem)
By ASA postulate,![\triangle AED\cong \triangle BEC](https://tex.z-dn.net/?f=%5Ctriangle%20AED%5Ccong%20%5Ctriangle%20BEC)
By CPCTC,
and ![CE\cong EA](https://tex.z-dn.net/?f=CE%5Ccong%20EA)
⇒ BE= ED and CE=EA
By the definition of bisector, AC and BD bisect each other.
Answer:
the answer is 9
Step-by-step explanation:
Answer:
its 4
Step-by-step explanation:
a 1 = 3 , a n = a n - 1 + 2
because if you aply this to the shapes that you see at problem 21 you will see that it meaches them
The coordinates would surely be -9,15
Answer: 2(0) + 8 does not equal 12, not a solution.
2(2) +8 = 12 yes it is a solution
2(-3) + 8 does not equal 12, not a solution
2(5) + 8 does not equal 12, not a solution.
Step-by-step explanation:
Looks like you need to plug in each y value given and multiplied by 2 and add 8
2(0) + 8 does not equal 12, not a solution.
2(2) +8 = 12 yes it is a solution
2(-3) + 8 does not equal 12, not a solution
2(5) + 8 does not equal 12, not a solution.