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3 years ago

7

You and three friends earn money by painting houses. You agree to split the profits equally. You buy brushes, tape, and paint fo

r $750. If your total income is $2,600, how much is your share of the profit?

1 answer:

tatuchka [14]3 years ago

4 0

(750-2600)*1/4=?? Hope it helps :-)

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Give an example of when you had to prove something, and how you did it!

Marizza181 [45]

Answer:

Just practice ,know different ways of solving it ,gain experince ,be smart and skilled.

Step-by-step explanation:

if you want to prove anuthing then go with the concept accoeding to the nature of the problem and there are almost many ways to prove anything so don't waste your time on way get on to the other ways.

It may not get proved at first time so keep on doing questions and when you have gained experience you know every nature of problems and then you are skilled properly.

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3 years ago

Kaylis [27]

Answer:

9cm

Step-by-step explanation:

making perpendicular "A" from center "O"

we get,OA=4cm(half of 8cm)

Now,

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h^2=p^2+b^2

5^2=4^2+b^2

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2 years ago

Please do this I need help ASAP

Doss [256]

Answer:

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3 years ago

How can you solve an equation with a variable on ni tu sides?

Vesnalui [34]

Answer:

Subtract from both sides of the equation the term you don't want

Step-by-step explanation:

In solving equations, you generally want to "undo" operations that are done to the variable. Addition is "undone" by adding the opposite (that is, subtracting the amount that was added). Multiplication is "undone" by division.

If you have variables on both sides of the equation, pick one of the variable terms and subtract it from both sides of the equation.

<u>Example</u>

2x = x +1

If we choose to subtract x, then we will have a variable term on the left and a constant term on the right:

2x -x = x -x +1 . . . . . . . x is subtracted from both sides

x = 1 . . . . . . simplify

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Note that we purposely set up this example so that removing the variable term from the right side caused the variable term and constant term to be on opposite sides of the equal sign. It may not always be that way. As long as you remember that an unwanted term can be removed by subtracting it (from both sides of the equation), you can deal with constant terms and variable terms no matter where they appear.

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<em>Additional Comment</em>

It usually works well to choose the variable term with the smallest (or most negative) coefficient. That way, when you subtract it, you will be left with a variable term that has a positive coefficient.

3 0

3 years ago

Given: △ABC, AB=5 square root 2 <br><br>m∠A=45°, m∠C=30°<br><br>Find: BC and AC

hichkok12 [17]

Answer:

Part a) $BC=10\ units$

Part b) $AC=13.66\ units$

Step-by-step explanation:

step 1

Find the length side BC

Applying the law of sines

we know that

$\frac{AB}{sin(C)}=\frac{BC}{sin(A)}$

we have

$AB=5\sqrt{2}\ units$

$A=45^o$

$C=30^o$

substitute

$\frac{5\sqrt{2}}{sin(30^o)}=\frac{BC}{sin(45^o)}$

solve for BC

$BC=\frac{5\sqrt{2}}{sin(30^o)}(sin(45^o))$

$BC=10\ units$

step 2

Find the measure of angle B

we know that

The sum of the interior angles in a triangle must be equal to 180 degrees

so

$m\angle A+m\angle B+m\angle C=180^o$

substitute the given values

$45^o+m\angle B+30^o=180^o$

$75^o+m\angle B=180^o$

$m\angle B=180^o-75^o$

$m\angle B=105^o$

step 3

Find the length side AC

Applying the law of sines

we know that

$\frac{AB}{sin(C)}=\frac{AC}{sin(B)}$

we have

$AB=5\sqrt{2}\ units$

$A=45^o$

$B=105^o$

substitute

$\frac{5\sqrt{2}}{sin(30^o)}=\frac{AC}{sin(105^o)}$

solve for AC

$AC=\frac{5\sqrt{2}}{sin(30^o)}(sin(105^o))$

$AC=13.66\ units$

4 0

2 years ago