Answer:80
Step-by-step explanation:
Answer:
thats so deep
<em>i</em><em> </em><em>see</em><em> </em><em>where</em><em> </em><em>you</em><em> </em><em>are</em><em> </em><em>coming</em><em> </em><em>from</em><em> </em><em>and</em><em> </em><em>i</em><em> </em><em>see</em><em> </em><em>ur</em><em> </em><em>point</em>
<em>ppljust</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>stop</em><em> </em><em>being</em><em> </em><em>selfish</em><em> </em><em>an</em><em> </em><em>helo</em><em> </em><em>eachother</em><em> </em><em>wetre</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>pandemic</em><em> </em><em>for</em><em> </em><em>christs</em><em> </em><em>sake</em>
Next multiples of the unit fraction 1/5 are
2/5
3/5
4/5
5/5 = 1
Hope this helps.. :)
Answer:
1.30 p.M.
Step-by-step explanation:
The factory whistle blowed at 1:00 p.M, and it blows every 30 minutes, so it will blow again at 1:30 p.M.
The clock tower chimed at 1.00 p.M., and it chimes every 15 minutes, so it will chime again at 1:15 p.M, and after that, it will chime again at 1:30 p.M.
So, you will hear them both at the same time at 1:30 p.M.
We can also solve this problem using LCM:
the least commom multiple between 15 and 30 is 30, so we just need to sum 30 to the inicial time (1:00 p.M.), so the time they will "find each other" again is 1.30 p.M.