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natima [27]
3 years ago
11

5. Simplify when a = 4 and b = 3; 2a – 21 ÷ b *

Mathematics
2 answers:
Sever21 [200]3 years ago
8 0

Answer:

1

Step-by-step explanation:

insert the values for a and b and solve.

kow [346]3 years ago
4 0
The answer is one because of pemdas but first you fill the letters with the suppose number and then do your pemdas steps
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5 weeks = _____days
Gennadij [26K]
1 week is 7 days.
5 times 7 is 35.
35 days.
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3 years ago
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Evaluate the expression when m = 2.
dalvyx [7]
11 - 3m   (replace m with 2)
11-3*2
11 - 6
5

The answer is A. 5

6 0
3 years ago
Read 2 more answers
How do you do this question?
Lena [83]

Step-by-step explanation:

The Taylor series expansion is:

Tₙ(x) = ∑ f⁽ⁿ⁾(a) (x − a)ⁿ / n!

f(x) = 1/x, a = 4, and n = 3.

First, find the derivatives.

f⁽⁰⁾(4) = 1/4

f⁽¹⁾(4) = -1/(4)² = -1/16

f⁽²⁾(4) = 2/(4)³ = 1/32

f⁽³⁾(4) = -6/(4)⁴ = -3/128

Therefore:

T₃(x) = 1/4 (x − 4)⁰ / 0! − 1/16 (x − 4)¹ / 1! + 1/32 (x − 4)² / 2! − 3/128 (x − 4)³ / 3!

T₃(x) = 1/4 − 1/16 (x − 4) + 1/64 (x − 4)² − 1/256 (x − 4)³

f(x) = 1/x has a vertical asymptote at x=0 and a horizontal asymptote at y=0.  So we can eliminate the top left option.  That leaves the other three options, where f(x) is the blue line.

Now we have to determine which green line is T₃(x).  The simplest way is to notice that f(x) and T₃(x) intersect at x=4 (which makes sense, since T₃(x) is the Taylor series centered at x=4).

The bottom right graph is the only correct option.

3 0
3 years ago
Please help, and explain how to solve the problem.
marishachu [46]

Answer:

7 and 9

Step-by-step explanation:

6 0
3 years ago
A football is kicked from the ground and follows the graph of the function y = –t2 + 3t, where y represents height and t represe
vesna_86 [32]

Answer:

The height of the objects are the same after 2 seconds.

Step-by-step explanation:

In order to calculate at which time both objects have the same height we need to find the value of t that makes both equations equal. Therefore:

-t^2 + 3t = -t + 4\\t^2 - 3t - t + 4 = 0\\t^2 - 4t + 4 = 0\\t_{1,2} = \frac{-(-4) \pm \sqrt{(-4)^2 - 4*1*4}}{2*1} = \frac{4 \pm \sqrt{16 - 16}}{2}\\t_{1,2} = \frac{4}{2} = 2

The height of the objects are the same after 2 seconds.

8 0
3 years ago
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