Answer:
<u>Based on the results the boutique could be located there.</u>
<u>Step-by-step explanation:</u>
Note: The average income (the mean) is calculated by summing the total incomes then divided by the total sample–9.
The mean ù (average income) = $28,000 + $24,000 + $26,000 + $25,000 + $23,000 + $27,000 + $26,000 + $22,000 + $24,000= $225,000/9= $25,000 (which is ≥ $25,000.
Based on the results of the p-value, using the 5% significant level <em>we fail to reject the null hypothesis</em> (ú≥25,000).
Answer:
g(6) = 71
f(11) = 62
Step-by-step explanation:
Let's solve g(6) first
Plug 6 into x
g(6) = 2(6)^2 - 1
g(6) = 2(36) - 1
g(6) = 72 - 1
g(6) = 71
Now let's solve f(11)
f(11) = 5(11) + 7
f(11) = 55 + 7
f(11) = 62
<em>Thus, out answers are 71 and 62 respectively</em>
Add 37 + 9 = 46
If thats not your answer theres more.
46 divided by 5 = 9.2
To find the answer, you need to divide 90.5 by 4. The answer to that is 22.625, and if you want to check the answer, 22.625 x 4 = 90.5. Hope this helps :)
Answer:
The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%
Step-by-step explanation:
For a normal random variable with mean Mu = 3.2 and standard deviation sd = 0.8 there is a distribution of the sample mean (MX) for samples of size 4, given by:
Z = (MX - Mu) / sqrt (sd ^ 2 / n) = (MX - 3.2) / sqrt (0.64 / 4) = (MX - 3.2) / 0.4
For a sample mean of 3.0, Z = (3 - 3.2) / 0.4 = -0.5
For a sample mean of 3.0, Z = (4 - 3.2) / 0.4 = 2.0
P (3.2 <MX <4) = P (-0.5 < Z <2.0) = 0.6687.
The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%