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nexus9112 [7]
3 years ago
15

(Long division)

align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
pav-90 [236]3 years ago
7 0

Answer:

hope it's helpful

┐( ∵ )┌

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Of a triangle
arsen [322]

Complete question is attached.

Answer:

a) ED = 6.5 cm

b) BE = 14.4 cm

Step-by-step explanation:

From the triangle, we are given the following dimensions:

AB = 20 cm

BC = 5 cm

CD = 18 cm

AE = 26 cm

We are asked to find length of sides ED and BE.

a) Find length of ED.

From the triangle Let's use the equation:

\frac{AB}{BC} = \frac{AE}{ED}

Cross multiplying, we have:

AB * ED = AE * BC

From this equation, let's make ED subject of the formula.

ED = \frac{AE * BC}{AB}

Let's substitute figures,

ED = \frac{26 * 5}{20}

ED = \frac{130}{20} = 6.5

Therefore, length of ED is 6.5 cm.

b) To find length of BE, let's use the equation:

\frac{AB}{AC} = \frac{BE}{CD}

Cross multiplying, we have:

AB * CD = AC * BE

Let's make BE subject of the formula,

BE = \frac{AB * CD}{AC}

From the triangle, length AC = AB + BC.

AC = 20 + 5 = 25

Substituting figures, we have:

BE = \frac{20 * 18}{25}

BE = \frac{360}{25} = 14.4

Therefore, length Of BE is 14.4cm

7 0
3 years ago
What is a value between 1/4 and 1/3 is
yaroslaw [1]

9514 1404 393

Answer:

  2/7

Step-by-step explanation:

Any unit fraction with a denominator between 3 and 4 will be between 1/3 and 1/4. For example, ...

  1/3.5 = 2/7 . . . . is between 1/3 and 1/4

__

You can also go at this considering decimal equivalents.

  1/4 = 0.25

  1/3 = 0.333... (repeating)

So, decimal numbers like 0.26, 0.295, 0.3330 are all values that are between 1/4 and 1/3.

6 0
3 years ago
What is the smallest of 3 consecutive positive integers if the product of the smaller two integers is 5 less than 5 times the la
Irina18 [472]
So consecutive intergers are 1 away from each other so
the numbers are
x,x+1,x+2
if the product (multily) of 2 smaeller is 5 less than 5 times largest so
(x times (x+1)) is 5 less than 5 times (x+2)
(x times (x+1))=-5+5(x+2)
pemdas
distribute using distributiver property
a(b+c)=ab+ac so
x times (x+1)=x^2+x
5(x+2)=5x+10
we have
x^2+x=-5+5x+10
add like terms
x^2+x=5x+5
subtract (5x+5) from both sides
x^2-4x-5=0
factor by find what 2 numbers add to -4 and multply to get -5
numbers are 1 and -5
so we do
(x+1)(x-5)=0
sete each to zero
x+1=0
x-5=0

x+1=0
sbtract 1
x=-1
we want positie so thisis wrong answer

x-5=0
add 5
x=5
subsitute
x,x+1,x+2
5,5+1,5+2
5,6,7


smalles is 5



4 0
3 years ago
Question 10 Express 40 as a product of prime factors​
Step2247 [10]

Answer:

2 x 2 x 2 x 5

Step-by-step explanation:

The first few prime numbers:  {2, 3, 5, 7, 11, 13, 17, 19}

One way to start is to divide by the first prime until you can't do that any more, then try the next prime and so on until all the numbers in your list are prime.

40 = 2(20)  divide 20 by 2 again

40 = 2(2)(10)  divide 10 by 2 again

40 = 2(2)(2)(5) stop--all factors are prime.

5 0
3 years ago
Help with my math homework
sertanlavr [38]

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bit.^{}ly/3a8Nt8n

5 0
3 years ago
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