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melisa1 [442]
4 years ago
5

3 over 2 divided 1 over 4 n is between

Mathematics
2 answers:
Yuki888 [10]4 years ago
3 0
It is between 5 and 7.
natulia [17]4 years ago
3 0
3/2 divided by 1/4 right?
It equals 3/8 if you simplify it to a decimal it's .375
Simplifying to a percent? Move decimal two places to the right. Between 7 and 5. 37.5%; You can round that if you like to the nearest percent, 38%

It's not what you asked for but that's just a little extra stuff. I hope that helps. :)
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Musya8 [376]

Answer: A

Step-by-step explanation: A function means that your x can only have one y but your y can have multiple x's.

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3 years ago
Distrubutive property<br> (m-3)(-10)?
mrs_skeptik [129]

Answer: -10m + 30

Step-by-step explanation:

<u>Given expression</u>

(m - 3) (-10)

<u>Expand parentheses and apply the distributive property</u>

=m · (-10) - 3 · (-10)

<u>Simplify by multiplication</u>

=\boxed{-10m+30}

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4 0
3 years ago
What is the simplified form of 2n+3(n+4)
Andrews [41]

Answer:

5n + 12

Step-by-step explanation:

Perform the indicated multiplication.  Then combine like terms:

2n + 3n + 12 = 5n + 12 (answer)

5 0
3 years ago
Congruent triangle measures.​
Charra [1.4K]

Answer:

3x=4x-9(By CPCT)

x=9

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5 0
3 years ago
You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o
Aleksandr [31]

Answer:

Therefore the circumference of the circle is =\frac{20\pi}{4+\pi}

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

\Rightarrow s=\frac{10-\pi r}{2}

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

A=\pi r^2+ (\frac{10-\pi r}{2})^2

\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2

\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}

\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25

For maximum or minimum \frac{dA}{dr}=0

Differentiating with respect to r

\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi

Again differentiating with respect to r

\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}    > 0

For maximum or minimum

\frac{dA}{dr}=0

\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0

\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}

\Rightarrow r=\frac{10}{4+\pi}

\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0

Therefore at r=\frac{10}{4+\pi}  , A is minimum.

Therefore the circumference of the circle is

=2 \pi \frac{10}{4+\pi}

=\frac{20\pi}{4+\pi}

4 0
3 years ago
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