The best and most correct answer among the choices provided by the question is the third choice .
In constructing a parallel line, "<span>Without changing the width of the compass, place the compass at S or P and draw an arc similar to the one drawn."</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
Answer: OPTION A.
Step-by-step explanation:
You know that the rule that will be used for the translation of the figure ABC is:
→![(x-3,\ y+4)](https://tex.z-dn.net/?f=%28x-3%2C%5C%20y%2B4%29)
You can observe in the figure that the coordinates of the point A is this:
![A(1,1)](https://tex.z-dn.net/?f=A%281%2C1%29)
Then, in order to find the coordinates that will best represent point A', you need to subtract 3 from the x-coordinate of the point A and add 4 to the y-coordinate of the point A:
Answer:
shortest side= x
longest side= x+8
other side= 3x
x+x+8+3x= 33
5x+8=33
5x= 25
x= 5
shortest side= x= 5
longest side= x+8= 5+8= 13
other side= 3x= 3(5)=15
Step-by-step explanation:
I'm assuming you're looking for the dimensions of the plot. I'm going with that. ;) If the length of the plot is 5 meters longer than the width, then L = w + 5. The area for a rectangle is L*w, and we have an area value of 20,000 so our formula is 20000=(w+5)(w) and
![20,000=w^2+5w](https://tex.z-dn.net/?f=20%2C000%3Dw%5E2%2B5w)
. We will bring the 20,000 over by subtraction and set the polynomial equal to 0 to factor and solve for w.
![w^2+5w-20,000=0](https://tex.z-dn.net/?f=w%5E2%2B5w-20%2C000%3D0)
Solving for w we get values of w=138.9 and -143.9. Of course the 2 things in math that will never EVER be negative are time and distance/length, so -143.9 is out. Our width is 138.9 and the length is 138.9 + 5 so the length is 143.9. And there you go! Hope that's what you needed!