Answer:
C. (-x, y)
Step-by-step explanation:
If you look at the graph the rectangle with the D', E', F', and G'. This is the one we are looking at.
It was rotated on the y-axis. and it stayed in the positive y.
It went to the negative x though.
C. (-x, y) is your answer.
Answer:
The launch angle should be adjusted to 30.63°
Step-by-step explanation:
The range of a projectile which is the horizontal distance covered by the projectile can be expressed as;
R =(v^2 sin2θ)/g
Where
R = range
v = initial speed
θ = launch angle
g = acceleration due to gravity
For the case above. When the projectile is launched at angle 13° above the horizontal.
θ1 = 13
R1 = (v^2 sin2θ1)/g
R1 = (v^2 sin26°)/g ....1
For the range to double
R2 = (v^2 sin2θ)/g .....2
R2 = 2R1
Substituting R2 and R1
(v^2 sin2θ)/g = 2 × (v^2 sin26°)/g
Divide both sides by v^2/g
sin2θ = 2sin26
2θ = sininverse(2sin26)
θ = sininverse(2sin26)/2
θ = 30.63°
Answer:
b=2
Step-by-step explanation:
Get rid of the parenthesis using distributive property:
6b+12+12b+6=54
Simplify
18b+18=54
subtract 18 from both sides
18b=36
divide by 18 on both sides
b=2
Answer:
1527.83 quarters
Step-by-step explanation:
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